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Need help with E and F please.
3. The beam shown in the figure below is...
A reinforced concrete cantilevered beam with a span of 5 m extends from the wall, as shown in the...
A reinforced concrete cantilevered beam with a span of 5 m extends from the wall, as shown in the figure below. The beam has a rectangular cross-section and supports a uniform dead load (DL) of 15 kN/m (excluding the self-weight) and a uniform live load (LL) of 25 kN/m. The beam width is restricted to 400 mm. Use 10M stirrups and 25M bars for tension steel. The maximum aggregate size is 20 mm. 1ie 5.5. beam is located in the...
Name: Date: 2. (+35) Design a typical interior tension-reinforced T-beam to resist positive moment. Beam dimension...
Name: Date: 2. (+35) Design a typical interior tension-reinforced T-beam to resist positive moment. Beam dimension is given. The service loads are 150 psf dead load (doesn't include the beam weight) and 350 psf live load. The beam is on a simple span of 20 ft. Use f:=4000 psi for strength concrete and fy=60000 psi for steel reinforcement. 8-0* (typ.)
all parts A simply supported concrete beam is to be designed to span 8m. The beam...
all parts
A simply supported concrete beam is to be designed to span 8m. The beam is required to resist a dead load of 40 kN/m (which includes an allowance for self-weight) and an imposed load of 20 kN/m Calculate the ultimate design load that the beam will be required to resist and hence calculate the ultimate design moment. (10 Marks] b) Choose an appropriate depth and width of the beam. [5 marks] c) Calculate an appropriate amount of reinforcing...
I just need help with (I). I can not seem to find the self-weight equation to...
I just need help with (I). I can not seem to find the self-weight
equation to add to my dead load.
1. A reinforced slab built integrally with beam consists of four spans (8' 6" on- center). The clear span of the slab is 7' 6" for all spans including the end span. The service live load is 160 psf and the service dead load is 30 psf (excluding self-weight). Given: f'.= 4,000 psi, normal weight concrete, fy= 60,000 psi....
i) For the beam shown in Fig. 1, if the live load on the beam is...
i) For the beam shown in Fig. 1, if the live load on the beam is 20 k/ft and the dead load including the self-weight is 15 k/ft, 1. how to distribute the load in order to get: a) maximum positive moment and b) maximum negative moment. 2. calculate the values of maximum positive and negative moments 3. suggest the locations of the longitudinal steel bars? 20 ft 5 ft
Please answer the question. The beam should be 35 ft. long for both pictures. (disregard the...
Please answer the question. The beam should be 35 ft. long for
both pictures. (disregard the 25 ft. length. it should be 35 ft.)
thank you
Reinforced Concrete
6-18%20(1).pdf Due: 06 March 2018 The beam shown in the figure is subjected to a uniformly distributed dead load (without including self-weight) equal to 0.5 kip/ft, and a uniformly distributed live load of 1.3 kip/ft. You may initially estimate the beam weight to be about 0.3 kip/ft, but you must verify and...
A simply supported beam as shown in the figure. The beam section is W18x211. The beam...
A simply supported beam as shown in the figure. The beam section is W18x211. The beam must support its own weight and must carry the following loading: Super-imposed distributed dead load = 0.25 kip/ft Distributed live load = 1 kip/ft Concentrated dead load = 12 kip The beam span L = 26 ft and the distance of the concentrated load from the right support a=6 ft. Consider analy- sis of beam subjected to load combination 1.2 dead + 1.6 live....
The reinforced concrete beam shown in Figure-2 is to be subjected to the following uniformly distributed...
The reinforced concrete beam shown in Figure-2 is to be subjected to the following uniformly distributed loads over the entire length: DL = 14 kn/m (including self-weight) and LL = 20kN/m, fc = 32 MPa. For architectural reasons the beam width is set at 500 mm. Determine the effective depth required if ku = 0.25 for the section of maximum positive bending moment. Then design the reinforcement required. zin Figure-2
The T-beam shown in Figure 1 supports the un-factored dead load of 1.4 kips/ft and live...
The T-beam shown in Figure 1 supports the un-factored dead load
of 1.4 kips/ft and live load of 1.5 kips/ft. The dead load does not
include the self-weight of the beam. The material properties are as
follows: fc’=3000 psi; fy=60,000 psi. Design the shear
reinforcement (stirrups). Plot the stirrups distribution along the
span of the beam.
DL= 1.4 kips/ft ; L2=1.5 kips/Ft * 75 Sz=7 X * b=3616. hr-6in k ) انا امه hw-lain + * bw=12 in
4.2 (a) Design the reinforcement for the beam shown in the figure for Problem 4.2, if...
4.2 (a) Design the reinforcement for the beam shown in the figure for Problem 4.2, if the dead load moment is 90 ft-kips and the live load moment is 140 ft-kips. (b) Determine the maximum tension reinforce- ment A, permitted for this beam by ACI- 9.3.3.1 and for a tension-controlled section. - 48" (1.2 m) - 4" (100 mm) 24" (610 mm) - 15"- (380 mm) Problem 4.2
A reinforced concrete cantilevered beam with a span of 5 m extends from the wall, as shown in the figure below. The beam has a rectangular cross-section and supports a uniform dead load (DL) of 15 kN/m (excluding the self-weight) and a uniform live load (LL) of 25 kN/m. The beam width is restricted to 400 mm. Use 10M stirrups and 25M bars for tension steel. The maximum aggregate size is 20 mm. 1ie 5.5. beam is located in the...
Name: Date: 2. (+35) Design a typical interior tension-reinforced T-beam to resist positive moment. Beam dimension is given. The service loads are 150 psf dead load (doesn't include the beam weight) and 350 psf live load. The beam is on a simple span of 20 ft. Use f:=4000 psi for strength concrete and fy=60000 psi for steel reinforcement. 8-0* (typ.)
all parts
A simply supported concrete beam is to be designed to span 8m. The beam is required to resist a dead load of 40 kN/m (which includes an allowance for self-weight) and an imposed load of 20 kN/m Calculate the ultimate design load that the beam will be required to resist and hence calculate the ultimate design moment. (10 Marks] b) Choose an appropriate depth and width of the beam. [5 marks] c) Calculate an appropriate amount of reinforcing...
I just need help with (I). I can not seem to find the self-weight
equation to add to my dead load.
1. A reinforced slab built integrally with beam consists of four spans (8' 6" on- center). The clear span of the slab is 7' 6" for all spans including the end span. The service live load is 160 psf and the service dead load is 30 psf (excluding self-weight). Given: f'.= 4,000 psi, normal weight concrete, fy= 60,000 psi....
i) For the beam shown in Fig. 1, if the live load on the beam is 20 k/ft and the dead load including the self-weight is 15 k/ft, 1. how to distribute the load in order to get: a) maximum positive moment and b) maximum negative moment. 2. calculate the values of maximum positive and negative moments 3. suggest the locations of the longitudinal steel bars? 20 ft 5 ft
Please answer the question. The beam should be 35 ft. long for
both pictures. (disregard the 25 ft. length. it should be 35 ft.)
thank you
Reinforced Concrete
6-18%20(1).pdf Due: 06 March 2018 The beam shown in the figure is subjected to a uniformly distributed dead load (without including self-weight) equal to 0.5 kip/ft, and a uniformly distributed live load of 1.3 kip/ft. You may initially estimate the beam weight to be about 0.3 kip/ft, but you must verify and...
A simply supported beam as shown in the figure. The beam section is W18x211. The beam must support its own weight and must carry the following loading: Super-imposed distributed dead load = 0.25 kip/ft Distributed live load = 1 kip/ft Concentrated dead load = 12 kip The beam span L = 26 ft and the distance of the concentrated load from the right support a=6 ft. Consider analy- sis of beam subjected to load combination 1.2 dead + 1.6 live....
The reinforced concrete beam shown in Figure-2 is to be subjected to the following uniformly distributed loads over the entire length: DL = 14 kn/m (including self-weight) and LL = 20kN/m, fc = 32 MPa. For architectural reasons the beam width is set at 500 mm. Determine the effective depth required if ku = 0.25 for the section of maximum positive bending moment. Then design the reinforcement required. zin Figure-2
The T-beam shown in Figure 1 supports the un-factored dead load
of 1.4 kips/ft and live load of 1.5 kips/ft. The dead load does not
include the self-weight of the beam. The material properties are as
follows: fc’=3000 psi; fy=60,000 psi. Design the shear
reinforcement (stirrups). Plot the stirrups distribution along the
span of the beam.
DL= 1.4 kips/ft ; L2=1.5 kips/Ft * 75 Sz=7 X * b=3616. hr-6in k ) انا امه hw-lain + * bw=12 in
4.2 (a) Design the reinforcement for the beam shown in the figure for Problem 4.2, if the dead load moment is 90 ft-kips and the live load moment is 140 ft-kips. (b) Determine the maximum tension reinforce- ment A, permitted for this beam by ACI- 9.3.3.1 and for a tension-controlled section. - 48" (1.2 m) - 4" (100 mm) 24" (610 mm) - 15"- (380 mm) Problem 4.2
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