Question

Consider the following competing hypotheses and accompanying sample data. (You may find it useful to reference the a table: z table or ttable) He: P1 - P2 = 0.20 HA: P1 - P20.20 25 points *1 = 126 y = 243 X2 = 125 = 480 8 03.06.08 a. Calculate the value of the test statistic. (Round Intermediate calculations to at least 4 decimal places and final answer decimal places.) eBook Test statistic References b. Find the p-value. 0.01 s p-value <0.025 0.025 s p-value <0.05 0.05 s p-value < 0.10 p-value 20.10 p-value <0.01 C. At the 5% significance level, what is the conclusion? Reject Ho: the difference between population proportions does not differ from 0.20 Do not reject Ho: the difference between population proportions differs from 0.20. Reject Ho: the difference between population proportions differs from 0.20. Do not reject Ho: the difference between population proportions does not differ from 0.20.

Answer 1

Ho IP,- P2 = 0.20 Ha : P, P2 & 0.20 (Two failed tept) We z table x =126 n = 243 *2 =125 n2 =480 P-X1126 9.6186 n. 243 = x2 125 = 0.2604 ñ 480-0 2604 p = x + X 126+125 = = 0.3472 243+ 480 hth a) Test Stalistic, (P-P2)-(P-R) Px(-2)(*) (0:5185 -0.2604)- 10.20-0-90) | 01397 1 0 5972) (örst tro) 0.2581 - 0.037482 = 6.886

b) P-value = {1-P(23689)] = [0.ooool using P-vake calentador Prvalue coool - c) The result is significant at Pk 4= 0.05 Since, P-value is less than the o=0005 So, we Reject Ho, the difference blu population Roportion does not differ from 0:20.