Question

Consider the following competing hypotheses and accompanying sample data (You may find it useful to reference the appropriate table: z table or t table) Ho: Pi - P22 MA: P1 - P2 @ X1 - 238 nu - 425 X2 - 263 n2 - 425 a. Calculate the value of the test statistic (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Test statistic rences b. Find the p-value. pvalue < 0.01 0.01 s p value < 0.025 O 0.025 s p value <0.05 0.05 s p-value <0.10 p.value 20.10 c. At the 5% significance level, what is the conclusion to the test? Reject Ho since the p-value is less than significance level Reject Ho since the p-value is greater than significance level Do not reject Ho since the p-value is less than significance level. Do not reject Hosince the p-value is greater than significance level. d. Interpret the results at a = 0.05. We conclude that the population proportions differ. We cannot conclude that the population proportions differ We conclude that population proportion 2 is greater than population proportion 1 We cannot conclude that population proportion 2 is greater than population proportion 1

Answer 1

Solutim Criven information Hopi - pz Lo ag Hip-hz 20 34 = 238 27 = 263 , = 425 m2 = 425 167-62-(bi-p2) ender Ho a) J (1.6") ( 1 + 1 ) The test Statistic - bu = 238 = 0.56 425 på = 263 - 0.618 Under Ho: 11 - 12 =O. 71- 238+ 263 = 0-5894 PS 225+425 (0.56-0-618) 1-1.768 Z - V0-5894 (1-0-5899) but ? 425 425

6 Looking at the direction of the alternate hypothesis | VH1 -9, 40, p-value = Polo (Z < Zobs) ZHN/01) = PHO (Z (-4-768) = $(--768) = 0.038 Therefore (0.025'2 0.0382005 3rd optim is correct At 5% los reject to as p-value is less than the level of significance level.. We reject Hoof p-value < level of significance first option is correct Therefore since we reject to acept Hy that is picke ie proportion & in population 2 is greater than the & population proportim in population t. Therefore optim 3 is correct

Please go through the solution. Thanks.