I did this chem experiment related to solubility and solubility product.
had 4 flask A B C & D, and saturated Ca(OH)2 with the following:
Flask A- Ca(OH)2 + 100mL of distilled water
Flask B - Ca(OH)2 + 100mL of 0.0125M NaOH
Flask C- Ca(OH)2 + 100mL of 0.025M NaOH
Flask D -Ca(OH)2 + 100mL of 0.050M Naoh
and titrated each with 0.1 M standardized HCL
solution.
the amount of HCl hat was required to neutralize each flask (in my
case ) was
flaskA- 7 mL
flaskB- 10mL
flaskC- 11mL
flask D- 12mL
The question being asked is to calculate the
equilibrium concentrations of OH- and Ca2+ in each case, and then
to calculate Ksp.
Please explain how to do the question.
I did this chem experiment related to solubility and solubility product. had 4 flask A B...
My question is regarding "solubility and solubility product ". Our lab had two parts: a) determine ksp of Ca(OH)2 b) observe how the presence of a commom ion, OH-, affects the solubility of Ca(OH)2 We had to titrate 0.1M HCl (0.1430 M to be exact) with the following: 1) Distilled water 2) 0.0125 M NaOH 3) 0.025M NaOH 4) 0.050M NaOH The volume of naoh used is 25ml The volume of HCl used was 1) 8 ml 2) 8.20ml 3)...
Solubility of Calcium Hydroxide At some temperature, the solubility of Ca(OH)2 is 0.0760 g/100mL. Calculate the concentrations of the Ca2+ and OH ions in a saturated solution of Ca(OH)2 and use these to calculate a value for Ksp of Ca(OH)2. [Ca2+ 1 pts Tries 0/99 Submit Answer [OH-] 1 pts Submit Answer Tries 0/99 Ksp 1 pts Tries 0/99 Submit Answer Calculate the volume of 0.0150 M HCl required to neutralize 10.00 mL of the saturated solution 1 pts Tries...
The concentration for HCl is 0.23182 M For Flask A volume is : 5.6 For Flask B Volume is : 12.7 For Flask C volume is : 20.3 For Flask D volume is : 29.7 SOLUBILITY PARTI MONROE D OM NOW O ! Oromo tration Sant Call Car , 40LOWY Discuss your results (no Error discussion). What happened as the concentraiton of NaOH in the solvent increased? What affect did it have on (Ca)..? Was the Kaffected? Should the Kp...
Chem experiment: Data: initial burette reading(ml): final burette reading: volume titrant added: trial 1: 32.00ml 48.0ml 16ml trial 2: 32.00ml 43.8ml 11.8ml trial 3: 34.00ml 43.9ml 9.9ml the volume of HCl (titrant) was == 1.26 mili-moles Complete the following ICE tables and use them to calculate the value of Ksp for all three trials. The initial concentrations of Ca2+ and OH– refer to the concentrations before any of the solid dissolved (i.e.when the solutions were originally made), and can therefore...
Part A and Part B. Also question #3-post lab. (its circled) A. Molar Solubility and Solubility Product of Calcium Hydroxide Trial I Trial 3 Trial 2 25.0 1. Volume of saturated Ca(OH), solution (mL) 2. Concentration of standardized HCl solution (molU/L) 3. Buret reading, initial (mL 4. Buret reading, final (mL) 5. Volume of HCI added (mL) 6. Moles of HCI added (mol) 7. Moles of OH" in saturated solution (mol) 8. (OH1, equilibrium (mol/L) 9. (Ca2 ], equilibrium (mol/L)...
Solubility Product Ksp for Ca(OH)2 is determined in two separate experiments, both at the same temperature. - by titration of hydroxide in a simple saturated solution of Ca(OH)2. - by titration of hydroxide in a 0.01 M CaCl2 solution saturated with Ca(OH)2. Identify which of the following statements is either completely "True" or at least partially "False" (assuming that the activity of each ion is equal to its molar concentration in each instance): a) True False You would expect the value...
ALT CHEM 125 Name Determining the Ksp of Calcium Hydroxide Calcium hydroxide is an ionie solid that is sparingly soluble in water. A saturated, aqueous, solution of Ca(OH), is represented in equation form as shown below. Ca(OH)2 (5) --- Ca' (aq) + 2OH(aq) The solubility product expression describes, in mathematical terms, the equilibrium that is established between the solid substance and its dissolved ions in an aqueous system. The equilibrium expression for calcium hydroxide is shown below. Kp - [Ca][OHT...
3.2-3.9 questions. based on number 3 statement. 3-2. Which of the followine is the chemical reaction for it a. Ca(OH) (s) 5 Ca (q) + 2OH() b. Cal (aq) + 2OH(aq) CaOH (s) c. Ca(OH)2 (s) + 2 HCI) CaCl(aq) + 2 H.00) d. CaCl(aq) + 2 H20d) to CaOH) ) + 2HCI) 3-3. How many moles of HCI were added? a. 0.0250 b. 0.000250 c. 0.000375 d. 0.250 3-4. How many moles of Cars were there in the supernatant?...
Can someone help me find 3a, b, c and 4b? I don't know how to do these. ? ×V-Lectures-Spring 2018-STX / My Lectures-Spring 2018-Mc Testing: introduction x Welcome to Chemistry 102ALON-CAPA PreLab X New Tab Amy c secure https: access3.lon-capaillinois.edu/res u uc/dmills CHEM103/NewLabs/SolubilityConstant PreLab problem?symb-uiu0%2fdmills%2fCHEM103%2f New Labs%2tSolubilityConstant. ? 1. The balanced equation for the dissolution of solid Ca(OH)2 in water is: Ca (OH)2(s)Ca2+(aq) + 20H (aq) Fill in the following blanks to give the correct Ksp expression for Ca(OH)2 (note:...
The experimental data needs to be made up using these instructions. Sample Data - Determination of a Solubility Product Constant Data For each titration trial, pick values that fall within the ranges given. Choose different numbers for Trials 1 and 2. Concentration of standard HCl solution (M): 0.050 Initial burette reading (ml): 1.00-2.00 Final burette reading (ml): 12.00-13.50 Volume of HCl added (mL): calculated Solution temperature (°C): 25.0 Complete the remaining calculations based on your entered data. Determination of a...