C2H5NH2 + H2O ---------> C2H5NH3+ + OH-
I 0.016 0 0
C -x +x +x
E 0.016-x +x +x
Kb = [C2H5NH3+][OH-]/[C2H5NH2]
6.4*10-4 = x*x/0.016-x
6.4*10-4 *(0.16-x) = x2
x= 0.0098
[OH-] =x= 0.0098M
Kw = [H+][OH-]
[H+] = Kw/[OH-]
= 1*10-14/0.0098
= 1.02*10-12 M >>>> answer
The base-dissociation constant of ethylamine (C_2H_5 NH_2) is 6.4 * 10^-4 at 25.0 degree C. In...
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Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you very much! 1) Z- is a weak base. An 0.350 M aqueous solution of NaZ is prepared. The pH of the solution was 8.93 at 25.0°C. The Kb of Z- is: 2) The base-ionization constant of ethylamine (C2H5NH2) is 6.4 x 10-4...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thanks guys! 1) Z- is a weak base. An 0.350 M aqueous solution of NaZ is prepared. The pH of the solution was 8.93 at 25.0°C. The Kb of Z- is: 2) The base-ionization constant of ethylamine (C2H5NH2) is 6.4 x 10-4 at 25.0...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you! 1) Z- is a weak base. An 0.350 M aqueous solution of NaZ is prepared. The pH of the solution was 8.93 at 25.0°C. The Kb of Z- is: 2) The base-ionization constant of ethylamine (C2H5NH2) is 6.4 x 10-4 at 25.0...
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