Z for 97% confidence interval = Z0.015 = 2.17
Confidence interval
= (1826.47 , 1923.53)
5. A bank manager wants to know the mean amount of mortgage paid per month by...
The manager of a paint supply store wants to estimate the actual amount of paint contained in 1-galion cans purchased from a nationally known manufacturer. The manufacturer's specifications state that the standard deviation of the amount of paint is equal to 0.01 gallon. A random sample of 50 cans is selected, and the sample mean amount of paint per 1-gallon can is 0.987 gallon. Complet parts (a) through (d). a Construct a 99% confidence interval estimate for the population mean...
Question Help The manager of a paint supply store wants to estimate the actual amount of paint contained in 1-gallon cans purchased from a nationally known manufacturer The manufacturer's specifications state that the standard deviation of the amount of paint is equal to 0.02 gallon. A random sample of 50 cans is selected, and the sample mean amount of paint per 1-gallon can is 0 989 gallon Complete parts (a) through (d) a Construct a 99% confidence interval estimate for...
The manager of a paint supply store wants to estimate the actual amount of paint contained in 11-gallon cans purchased from a nationally known manufacturer. The manufacturer's specifications state that the standard deviation of the amount of paint is equal to 0.040.04 gallon. A random sample of 5050 cans is selected, and the sample mean amount of paint per 11-gallon can is 0.9760.976 gallon. Complete parts (a) through (d). a. Construct a 9999% confidence interval estimate for the population mean...
A toy company wants to know the mean number of new toys per child bought each year. Marketing strategists at the toy company collect data from the parents of 50 randomly selected children. The sample mean is found to be 4.7 toys per child, and the sample standard deviation is calculated to be 1.5 toys per child per year. Assume that the population standard deviation is known to be 1.9 toys per child per year. Find the error of estimate...
The manager of the Inlet Square Mall, near Ft. Myers, Florida, wants to estimate the mean amount spent per shopping visit by customers. A sample of 20 customers had a sample mean of $49.35 and a sample standard deviation of $9.01. Find the 95% confidence interval for the population mean.
9.16 A bottled water distributor wants to determine whether the mean amount of water contained in 1-gallon bottles purchased from a nationally known water bottling company is actually 1 gallon. You know from the water bottling company specifications that the standard deviation of the amount of water per bottle is 0.02 gallon. You select a random sample of 50 bottles, and the mean amount of water per 1-gallon bottle is 0.995 gallon. a. Is there evidence that the mean amount...
all answers please 3. The teachers union is concerned about the amount of time teachers spend each week doing schoolwork at home. A simple random sample of 56 teachers had a mean of 8.0 hours per week working at home after school. Assume that the population standard deviation is 1.5 hours per week. a) Construct a 95% confidence interval estimate for the mean number of hours per week a teacher spends working at home. b) Does the confidence interval support...
%) 8.1.9-T Question Help The manager of a paint supply store wants to estimate the actual amount of paint contained in 1-gallon cans purchased from a nationally known manufacturer The manufacturers specifications state that the standard deviation of the amount of paint is equal to 0 03 gallon. A random sample of 50 cans is selected, and the sample mean amount of paint per 1-gallon can is 0 988 gallon. Complete parts (a) through (d) a Construct a 99% confidence...
A chain restaurant wants to estimate the population mean weight of one of their entrees. A random sample size n = 36 showed sample mean = 18 ounces with sample standard deviation s = 1.8 ounces. Create a confidence interval at 95% confidence for the population mean μ.
Based on a random sample of 1140 adults, the mean amount of sleep per night is 8.56 hours. Assuming the population standard deviation for amount of sleep per night is 1.3 hours, construct and interpret a 90% confidence interval for the mean amount of sleep per night. A 9090% confidence interval is (nothing,nothing). (Round to two decimal places as needed.) Interpret the confidence interval.