The positive and zero sequence networks of a 3-bus power system are shown below:
Determine the fault current on each phase for each of the following faults:
a) Solid 3-phase fault at bus 3
b) LG fault at bus 3 (on phase A)
c) LL fault at bus 3 (on phases B and C)
d) LLG fault at bus 3 (on phases B and C)
The positive and zero sequence networks of a 3-bus power system are shown below:
The zero-, positive-, and negative-sequence bus impedance matrices for a three bus power system are given below 5. T0.10 0.15 0.121 Bu0.15 0.10 0.08 pu [0.16 0.10 0.15] Lo.15 0.14 0.30 0.12 0.08 0.35 ZBus ZBus0.10 0.20 0.14 pu Determine the per unit fault current and the bus voltages during fault for (a) A bolted three-phase fault at bus 2. (b) A bolted single line-to-ground fault at bus 2. (c) A bolted line-to-line fault at bus 2 (d) A bolted...
The positive-sequence reactances for the power system shown in Figure 10.31 are in per unit on a common MVA base. Resistances are neglected and the negative-sequence impedances are assumed to be the same as the positive-sequence impedances. A bolted line-to-line fault occurs between phases b and c at bus 2.Before the fault occurrence, all bus voltages are 1.0 per unit. Obtain the positive-sequence bus impedance matrix.Find the fault current, the three-phase bus voltages during fault, and the line currents in...
The component parameters for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 120° pu and Zx-j0.1 pu. Table 1 Ratings X2-Xi (pu)Xo (pu) 0.05 0.10 0.20 0.20 Components G1, G2 200 MVA, 20 kV 0.10 0.10 0.10 0.10 T1, T2, T3200 MVA, 20/200 kV L1 200 MVA, 200 kV し2 200 MVA, 20 kV (a) Draw the three sequence networks and determine the per-unit Thevenin impedance of each sequence network seen from...
BUS 1 BUS 2 LINE 1 T1 L1 T2 G1 G2 R = 0,6 pu LINE 2 L2 T3 G3 BUS 3 a) For the above network, draw positive, negative and zero sequence networks (60 marks) b) Provide the main mathematical steps that will allow you to calculate the magnitude (in ampere) of the phase to phase fault current at BUS 1. As part of your answer you should show clearly, on a diagram, how the networks of part (a)...
Q2. (a) For the following system, please draw the complete positive-sequence, negative-sequence and zero-sequence network connection (phase A) for the double line-to-ground faults (phases B and C to ground faults) at bus M. XP XLu Eaz EGs Figure Q2. (b) For double line-to-ground faults at point M, please find the positive-sequence cuurent of phase A. The parameters are as follows: Prefault voltage Egi-120, Ea-10 E-10 (Per Unit) Parameters (Per Unit): Generators: Xa-X,-X,o = 0.2 , Xa,' = X,-= XG2-0.2 Transformers....
The single-line diagram of a three-phase power system is shown. Equipment ratings are given as follows: The inductor connected to generator 3 neutral has a reactance of \(0.05\) pu using generator 3 ratings as a base.1. Draw the zero-, positive-, and negative -sequence reactance diagrams using a \(1000 \mathrm{MVA}, 765 \mathrm{kV}\) base in the zone of line \(1-2\).2. Faults at bus 2 are of interest. Determine the Thevenin equivalent of each sequence network as viewed from the fault bus. Prefault voltage...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn 0.05 per unit on the motor base. Assume that Pre-fault voltage is takin as VF-1.0 ,0° per unit and Pre- fault load current and Δ-Y transformer phase shift are neglected In the...
For the system shown in Fig. P4.5 set up the positive, negative, and zero sequence networks in per unit on a 30-MVA base. As suming no load, reduce the three networks to equivalent single circuits, as shown in Fig. 4.13 for a fault at bus H. (This problem is continued in Problems 6.2, 6.3, and 7.4.) 7 GEN. 324.5 kV Line X = X 6A GEN 30 NVA 30 MVA 13.8 kV 13.8:34.5 kV X, X, 125 X = 68...
(10 points) For the power system shown below, sketch the sequence circuit connections for a 02, phase A to ground fault at bus B, and develop the equation for calculating the fault current in sequence coordinates. The sequence impedances of the generator and transformer are shown in the figure. T1 B (GENHH OH SLG FAULT Generator: Zs1 = Zs2, Zso, Y-grounded T1: Zy1 = Z12 = Zto, Delta-Wye Grounded Fault: Phase A to Ground, Z = 0
The positive, negative and zero sequence bus impedance and admittance matrices of a system are given as follows:\(Z^{+}=Z^{-}=j\left[\begin{array}{ccc}0.14 & 0.11 & 0.125 \\ 0.11 & 0.14 & 0.125 \\ 0.125 & 0.125 & 0.175\end{array}\right] \quad Y^{+}=Y^{-}=j\left[\begin{array}{ccc}-24 & 10 & 10 \\ 10 & -24 & 10 \\ 10 & 10 & -20\end{array}\right]\)\(Z^{0}=j\left[\begin{array}{ccc}0.10 & 0.10 & 0.10 \\ 0.10 & 0.30 & 0.20 \\ 0.10 & 0.20 & 0.30\end{array}\right] \quad Y^{0}=j\left[\begin{array}{ccc}-16.66 & 3.33 & 3.33 \\ 3.33 & -6.66 & 3.33...