Question

bilbecome famillar with t Objective design of other smchronos e pieos 2A Problem description six-state up-down co and Qo are required in the desidesi are rotvpulse to the REETInuo a posal state Se where the normal countet direcion Te the circuit in the initial st the RES hown in Fres flip-opw wi the RESET input is O during KESET Input of the couner th counting sequence is signal Cwa reversed irc- s an up-counter. The RES So 0. Ss S4 Figure 1 State diagram for a 6-state up-down counter Two designs are required: one using D-type flip-lops, another using JK-type fip- flops. For each design, follow the procedure listed below. (1) Construct a state diagram. (2) Construct a transition table. (3) Convert the transition table to next-state maps. (4) Obtain the excitation functions from the next-state maps. (5) Draw a schematic diagram. The counter sequence assigned to you can be found on pages 19-25. Two of the tates are unused. If for any reason the circuit strays from the normal counting sequence to an unused state, it must be able to return to the normal counting sequence. Thus the next state for each of the two unused states should be verified

Answer 1

Schematic \r\n J_2 = C (Q_1^bar Q_0^bar) + C^bar Q_1 Q_0 J_2 = C (Q_1^bar Q_0^bar) + C^bar Q_1 Q_0 k_2 = C^bar Q_0 + C Q_0^bar k_2 = C CirclePlus Q_0 J_1 = C^bar Q_2^bar Q_0 + C Q_2^bar Q_0^bar k_1 = C Q_0^bar + C^bar Q_0 k_1 = C CirclePlus Q_0 similarly k_0 = 1 J_0 = 1 \r\n Schematic \r\n JK flipflop excitation table for a D flip flop Q^+ < = D Q_2^+ < = D_2 Q_1^+ < = D_1 Q_0^+ < = D_0 Design for D flip flop D_2 = C^bar Q_1 Q_0 + C^bar Q_2 Q_0^bar + C Q_2 Q_1^bar Q_0 + C Q_2^bar Q_1^bar Q_0^bar D_2 = C^bar Q_1 Q_0 + C^bar Q_2 Q_0^bar + C Q_1^bar (Q_2^bar Q-0^bar + Q_2 Q_0) D_2 = C^bar Q_1 Q_0 + C^bar Q_2 Q_0^bar + C Q_1^bar (Q_2 CircleDot Q_0) D_1 = C^bar Q_1 Q_0^bar + C Q_1 Q_0 + C Q_2 Q_1^bar A_0^Bar + C^bar Q_2^bar Q_1^bar Q_0