Question

How many grams of NO2 are theoretically produced if we start with 1.20 moles of S and 9.90 moles of HNO3 Reaction: S + 6HNO3 H2SO4 + 6NO2 + 2H20 786 455 7.20 331 54.6

Answer 1

Date Page - Reaction! S + 6HNO3 Hy sou +6NO at 2 H₂O Initial 1. Romole s 9.90 moles HNO3. s. le of 6 moles of HNO3 react with I mole of S. I mole of HNO3 will react with 116 mole of s. 9.90 moles react with a 1x9.90 moles of s = 1665 moles of s. But we have only 1.20 mole of s, so, limiting dreagent is S. It will completely comsumed in the reaction. I mole a s produced - 6 mole No2 1920 moles as produced = 641.20 moles of No2 = 7.2 moles of No2 Мо 0.9 та Д е Мео - Ч. 0 3 | mol. I so No2 produced in grams - 7. 2 moles x 46.og moles = 3319 So, option (d) is correct. 3319 of No2 will be produced.