If the value of jump instruction is 0x8000000 and it is located at the memory address, 0x10000048, then the address being jumped to is:
0x80000000 |
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0x10000000 |
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0x10000004 |
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0x10000008 |
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0x10000048 |
If the value of jump instruction is 0x80000012 and it is located at the memory address, 0x10000044, then the address being jumped to is:
0x80000010 |
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0x10000040 |
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0x10000044 |
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0x10000048 |
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0x1000004C |
If the value of jump instruction is 0x8000000 and it is located at the memory address,...
Suppose the instruction j LABEL1 resides at memory address 0x04000000. What is the highest memory address (expressed in hex) to which this instruction can transfer control?
a. What is the purpose of the label instruction in the jump-to-label instruction pair? b. When the jump-to-label instruction is executed in what way are the jumped rungs affected? 12.
Given following registers and memory addresses contain the following values $t1 = 40 $t2 = 0x10000004 memory address 0x10000004 = 80 memory address 0x10000008 = 160 After execution of following instruction, fill the values that will be contained by each of the registers and memory address. If value is represented in hex then use the prefix 0x (e.g. 0x10000000) sw $t1, 4($t2) $t1 = $t2 = (0x10000004) = (0x10000008) =
Suppose that a beq instruction resides at memory address 0x08000000 and that the rightmost 16 bits within the machine code for the beq contains the value 0x00BB. To what value (expressed in hex) would the PC be set if the zero flag=1 when the beq instruction is executed?
Modefi the following circuit by adding one more Data Memory. instrucion[25-0.(left Shift Jump address (31-0 26 28 | PC + 4 [31-28] PC Src | M Mux 1u Add Branch Adder Add result XPC Src Mux 2 RegDste Shift left 2/ PC Mux 1 Select PC Adder Jum Branch AND Gate Instruction (31-26 Control ALUOP MemWrite AL RegWrite Instruction (25-21]Read ALU Src2 Mux register 1 Read Instruction 120-16)Readdata 1 PC Read address Instruction InstructionInstruction (15-11register 0-1 register 2 Zero LU...
Suppose the program counter (PC) is set to 0x30002000. Is it possible to use the jump (j) MIPS assembly instruction to jump directly to the instruction at 0x50003000? If yes, write the corresponding assembly instruction(s). If not, explain why and give other MIPS instruction(s) that can jump to this target address. (For this problem, assume that the instruction memory starts from 0x00000000 and goes to 0xFFFFFFFF.)
1. The instruction TRAP x25 causes the PC to be loaded with the memory address: a. x0025 b. x2500 c. the contents of x0025 d. x0250 2. The instruction TRAP x23 at location x4232, causes R7 to be loaded with: a. x4232 b. x4233 c. contents of x4232 d. contents of x4233 4. The execution of the JSR instruction at location x4202, causes R7 to be loaded with: a. x4200 b. x4201 c. x4202 d. x4203 5. Which instruction in...
A microprocessor has a decrement memory direct instruction, which subtracts 1 from the value in a memory location. The instruction has five stages: fetch opcode (two bus clock cycles), fetch operand address (five cycles), fetch operand (five cycles), subtract 1 from operand (four cycles), and store operand (two cycles). a. By what amount (in percent) will the duration of the instruction increase if we have to insert one bus wait state in each memory read and memory write operation? b....
Answer in hex . Instructions Data Ox12 Ox34 Ox56 Address 0x10000000 0x10000001 0x10000002 Ox10000003 0x10000004 Ox10000005 0x10000006 Ox10000007 Ox78 Ox9A OxBC OxDE OxFO QUESTION 6 What is the memory address that will be affected by the execution of the following instruction and what is its content sb $t0, 4($t0)
Problem 4 (15pts): hines iom address oing MIPS memory with data shown in hex, which are located in little-endian byte on rough 15. Show the result of the MIPS instruction "w Ss0, 4(Sa0)" for an byte orders, where $a0 4 Address Contents Address Contents 0a 1 b 2c 3d 8a 9b 10 b4 c5 6d 7e 8f 5f 13 14 15 70 (b) (10pts)Ass specified units. ume we have the following time, performance and architecture parameters in the Ec execution...