Solution :-
Given data:-
R = 9.10 ohm
L = 3.20 cm
B = 0.290 T
e = IR .......(1)
e = BLv......(2)
compare there two equation (1) and (2) we get
v = IR/BL
v = (8.6 x 10^-3 * 9.1 ) / ( 0.29 * 0.32 m )
v = 0.843 m/s
b) Counter-clockwise
part c)
P = I^2 *R
P = (8.6 x 10^-3)^2 * 9.1
P = 6.73 x 10^-4 W
part d )
Work is being done by the external force, which is transformed into internal energy in the resistor
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