Solution:
3.4.1 AND 3.4.2
AS CAN BE CONCLUDED FROM TABLE 5....FOR FIRST AND THE
LAST COMBINATION THE INPUTS ARE SAME AND THE LED GLOWS
BINARY INPUTS IN THE ORDER A3 A2 A1 A0 B3 B2 B1
B0
0000 0000
0010 0011
0111 0110
1100 0100
1101 1110
1110 1110
TABLE 5
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PART 3.5.1 AND 3.5.2
OUTPUTS
X3 X2 X1 X0 FOR
D1 = 0 AND
A3 A2 A1 A0 = 0000
A3 A2 A1 A0 = 0010
A3 A2 A1 A0 = 0111
A3 A2 A1 A0 = 1100
A3 A2 A1 A0 = 1101
A3 A2 A1 A0 = 1110
OUTPUTS
X3 X2 X1 X0 FOR
D1 = 1 AND
A3 A2 A1 A0 = 0000
A3 A2 A1 A0 = 0010
A3 A2 A1 A0 = 0111
A3 A2 A1 A0 = 1100
A3 A2 A1 A0 = 1101
A3 A2 A1 A0 = 1110
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PART 3.6
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LOX HE In-Use List --- @@@@ File Edit View Place MCU Simulate Transfer Tools Reports Options Window Help 6 % Esê non + the + d Oy 8 Y 0-0 Design Toolbox + MISC II Interactive AWAY Te C B D1 - CKT1 CKT1 XORA ХО. 0 Key = Space 7486N 2.5 V XORBA X1 А0. 7486N 2.5 V 0 Key = Space A1 110: 1 MEIRITION 0111 XORCA X2 1 Key = Space 7486N 2.5 V X3 A2 XORDA E 7486N 0 Key = Space A3 0 Key = Space 2.5 V Hierarchy Visibility Project View CKT1* Results Nets Components Copper layers Simulation For Help, press F1 CKT1: Simulating... Tran: 1.849 5
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Solution 3.6 Zobo/ min terms for which x=) are 1,2, 4 and 7 x = A B C + Ā B C + ABC + ABC 3.6-2 X= Ā B C + Ã Bēt ABC TABC A *(ệc sẽ) {8C + BC = A[B9c] + 4 [ BOC) let BOC=M > x= ĀM TAM - A OM X=4 0 B 0 C (M= 8 oc)
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