Question

1. Using the random number program, fill up an array with 100 random numbers between -30 and 30 and display it. Find out how many of those numbers in the array are positive, negative, even and odd. Display the results. Make sure you cover the special case. Your entire code should have only 1 FOR loop. You will not receive any credit if you use more than 1 loop. (50 points - 5pts for commenting and 45pts for successful execution)

C languge please !

Answer 1

CODE:-

#include <stdio.h>

#include <stdlib.h>

int main(void) {

int arr[100];

int i;

int positive = 0;

int negative=0;

int odds = 0;

int evens=0;

for(i=0;i<100;i++){ // this is the first and only for loop

arr[i] = (rand()%(61)) - 30; //rand() % (upper-lower+1))+lower;

// is used to calculate the random number between 2 numbers

if(arr[i]>0){ // if number is positive

positive++;

}else if(arr[i]<0){ // when number is negative

negative++;

} // special case is when number is zero, then is neither positive nor negative

if(arr[i]%2==0){ //if divisible by 2

evens++;

}

else{ // else

odds++;

}

printf("%i ",arr[i]);

}

printf("\n"); //printing the results

printf("Number of positive numbers are: %i\n",positive);

printf("Number of nehative numbers are: %i\n",negative);

printf("Number of even numbers are: %i\n",evens);

printf("Number of odd numbers are: %i\n",odds);

return 0;

}

main. E saving... 1 #include <stdio.h> 2 #include <stdlib.h> int main(void) { int arr[100]; int i; int positive = 0; int negative=0; int odds = 0; int evens=0; for(i=0;i<100; i++){ // this is the first and only for loop arr[i] = (rand()%(61)) - 30; //rand() % (upper-lower+1))+lower; // is used to calculate the random number between 2 numbers if(arr[i]>0){ // if number is positive positive++; }else if(arr[i]<0){ // when number is negative negative++; } // special case is when number is zero, then is neither positive nor negative if(arr[i]%2==0){ //if divisible by 2 evens++; else{ // else odds++; printf("%i ", arr[i]); } printf("\n"); //printing the results printf("Number of positive numbers are: %i\n", positive); printf("Number of nehative numbers are: %i\n", negative); printf("Number of even numbers are: %i\n",evens); printf("Number of odd numbers are: %i\n", odds); return 0;

OUTPUT:-

? clang-7 -pthread -lm -o main main.c ./main -1 24 -27 24 -23 19 17 29 -2 -7 -24 17 11 -10 -21 10 22 -11 -6 20 26 15 8 -22 0 -27 -15 18 30 28 -6 0 22 -1 -5 -30 -13 -18 -30 15 7 -24 3 -13 -2 1, 5 30 -11 -25 -7 -19 -30 -20 19 -21 10 24 -4 -3 25 -7 21 -5 -16 -8 22 -14, 9 -25 -14 -4 15 -6 29 -29 23 15 -28 -17 21 -2 -4 21 8 -16 -29 -11 -22 -3 16 -28 21 8 -1 -24 30 -7 -7 11 -2 Number of positive numbers are: 41 Number of nehative numbers are: 57, Number of even numbers are: 49 Number of odd numbers are: 51,

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