1. A portion of the stock has to be diluted for this purpose. We could take the required amount and then volume could be made up with Phosphate buffered saline.
10 microgram or 10000ng is present in 1000 microlitre (1ml)
then 67.5 ng will be present in 1000/ 10000 multiplied with 67.5
= 6.75microlitres
6.75microlitres from the stock has to be taken and PBS will be added to make up the volume 1ml.
2. 0.8g of NaCl has to be added to 100ml of sterilized water
3. Suppose, if we start with 100ml of 90% alcohol, we have to tkae 31.5ml of alcohol from it and water could be added to make up the volume to be 100ml, and the resulting solution will be of 30% concentration, i.e we wiill have 100ml of 30% alcohol.
4. for 4 making 4% paraformaldehyde, we have to take 8 grams of paraformaldehyde in 100ml of the buffer.The, glutaraldehyde has to be diluted 10 times from the stock solution with the buffer.
You are given a stock solution of ribosylated collagen. In order to complete your experiment, you...
How do I do the dilution calculations for this question? You will be given stock concentrations of both BSA and GAPDH at 4 mg/ml. Dilute the BSA and GAPDH to be used for the plate coat to a final concentration of 10 μg/ml in freshly prepared phosphate buffered saline (1 x PBS, 0.01M phosphate, 0.15M NaCl, pH 7.4).
Your stock solution is 10M NaCl. You want to make a 350mL solution of 450mm NaCl. How would you make this solution? Add 15.75 mL of water and 334.25 stock NaCl solution Add 15.75 mL of stock NaCl solution and 334.25 ml water Add 157.5 mL of stock NaCl solution and 192.5 ml water Add 157.5 mL of water and 192.5 mL stock NaCl solution
You are given a 2M stock solution of NaCl and are asked to make up 100 ml of a 1M solution of NaCl. How do you do that, using the stock solution and distilled water? Select one: O a. I would add 2 ml of the stock to 98 ml of water. O b. I would add 10 ml of the stock to 40 ml of water O c. I would add 20 ml of the stock to 80 ml...
Making Solutions Practice Problems: I. How would you prepare 100 ml of a 30% (w/v) solution of polyethylene glycol (PEG)? 2. How would you prepare 50 ml of a 9 % (w /v ) solution of NaCI? 3. How would you prepare 200 ml of 70 % ( v /v ) solution of ethanol from a stock of 95% ethanol? How would you prepare 200 ml of 0.3 M NaCl? (NaCl MW 58.44) 4. 5. How are 50 ml of...
1. Ifyou wanted to make a 4 M NaCl solution and you wanted a full Liter of it, how would you make it? Describe all of the steps. (Remember from lab, molecular weight of NaCl is 58.44) 2. Now describe how you would dilute this 4 MNaCl solution by a 1:10 dilution -how would you do this? Again, make 1 Liter. 3. Suppose you wanted a 2: 50 dilution of a stock solution, but you wanted 200 mL of it....
Can someone walk through a few simple algebraic solution-making problems? I know how to use formulas, such as C1V1 = C2V2, however I'm having issues with the conceptual part, mostly for when using two solutes. Problem #1: Make 200 mL of a saline that has 5 mMol NaCl and 15 mMol KCl. Stocks are 0.1 M NaCl & 0.2 M KCl. (and if it's simply the C1V1=C2V2 of one, and then the second, added together in a 200 mL flask...
From a 95% ethanol (ETOH) stock solution, you need to make 250 mL of 70% ETOH. How much stock and how much RO water do you need to make this solution- Show your work.
You have a 5.0 M copper sulfate stock solution and a 2 M NaCl stock solution. You wish to prepare a solution with a final concentration of 0.25 M copper sulfate and 0.25 M NaCl containing 330 mL of water as a solvent. How many milliliters of the NaCl stock solution would the solution contain?
1. How would you prepare 125 ml of a 10% (v/v) solution of acetic acid in H2O? 2. How would you prepare 60 ml of a 5% (W/V) NaCl solution in H20? 3. How would you prepare 3 ml of 82% solution A and 18% solution B? 4. 5 ml of a 2.0 mg/ml protein solution contains mg protein. a. If 1.0 ug/ml of pigment X shows an absorbance of 0.059 at 370nm, then what is the concentration of a...
Phosphate buffer (pH range 5.8 – 8.0). Assume you have prepared two separate stock solutions: Solution A: 0.1M solution of monobasic potassium phosphate (KH2PO4) and Solution B: 0.1M solution of dibasic potassium phosphate (K2HPO4) The equilibrium: H2PO4 - H+ + HPO4 2-; pKa= 6.86 In order to get 200 mL of the desired buffer, you take 50 mL of solution A, add to it some amount of solution B, and then adjust the total volume to 200 mL by adding...