sample mean = -1.875
t critical= 2.3646
sM = √(1.6421^2/8) = 0.5806
μ = M ± t(sM)
μ = -1.875 ± 2.3646*0.5806
μ = -1.875 ± 1.3729
95% CI [-3.25, -0.50].
You can be 95% confident that the population mean (μ) falls between -3.25 and -0.50
and from your 3. Award: 5 out of 10.00 points you did not The following table...
The following table contains information on matched sample values whose differences are normally distributed. (You may find it useful to reference the appropriate table: z table or t table) Number Sample 1 16 Sample 2 21 10 12 WN 00 O a. Construct the 90% confidence interval for the mean difference up. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval is...
The following table contains information on matched sample values whose differences are normally distributed. (You may find it useful to reference the appropriate table: z table or t table) NumberSample 1Sample 21162021213320224202251720614167161881821 a. Construct the 99% confidence interval for the mean difference μD. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.)
The following table contains information on matched sample values whose differences are normally distributed. (You may find it useful to reference the appropriate table: z table or t table) Number Sample 1 Sample 2 1 17 20 2 12 12 3 21 22 4 21 20 5 16 21 6 14 16 7 17 18 8 17 20 a. Construct the 90% confidence interval for the mean difference μD. (Negative values should be indicated by a minus sign. Round intermediate...
The following table contains information on matched sample values whose differences are normally distributed. (You may find it useful to reference the appropriate table: z table or t table) Number Sample 1 Sample 2 1 18 22 2 13 11 3 22 23 4 23 20 5 17 21 6 14 16 7 18 18 8 19 20 Construct the 99% confidence interval for the mean difference μD. (Negative values should be indicated by a minus sign. Round intermediate calculations...
The following table contains information on matched sample values whose differences are normally distributed. Use Table 2. Number Sample 1 Sample 2 1 16 20 2 12 13 3 20 22 4 20 22 5 17 20 6 14 16 7 16 18 8 18 21 a. Construct the 99% confidence interval for the mean difference μD. (Negative values should be indicated by a minus sign. Round all intermediate calculations to at...
The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the t table and the q table.) x−1x−1 = 25.3, n1 = 8; x−2x−2 = 31.5, n2 = 10; x−3x−3 = 32.3, n3 = 6; MSE = 27.2 a. Calculate 95% confidence intervals for μ1 − μ2, μ1 − μ3, and μ2 − μ3 to test for mean differences with Fisher’s LSD approach. (Negative values should be indicated...
Return to question Consider the following data drawn independently from normally distributed populations: (You may find it useful to reference the appropriate table: z table or t table) X1 = 30.5 012 = 96.3 ni = 27. x2 = 24.7 022 = 93.1 n2 = 26 a. Construct the 95% confidence interval for the difference between the population means. (Negative values should be indicated by a minus sign. Round all intermediate calculations to at least 4 decimal places and final...
Chapter 13 Analysis of Variance Saved Help Save & Exl Chec 3 The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the ttable and the gtable.) 10 points a. Calculate 99% confidence intervals for μ1-μ2, μ1 -μ3, and μ2-μ3 to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round...
CH13 Q3
The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) a. Calculate 99% confidence intervals for μ 1-2, μ1-#3, and μ2-#3 to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your answers to 2 decimal places.) Population Mean Differences Can...
The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the gtable.) X1 163, ni = 5; 2 = 171, n2 = 5; J3 = 166, n3 = 5; X4 = 158, n4 = 5; MSE = 41.2 a. Use Fisher's LSD method to determine which population means differ at a = 0.05. (Negative values should be indicated by a minus sign. Round intermediate...