Question

metis antibi hang on 11 Asaturated solution of an unknown salt has a density of 1.82 g/mL (1.00 g H:0, 0.82 g solute) at a resist temperature of 50°C. When the solution is cooled to 25°C, some of the unknown salt crystallizes out and Sofia the saturated solution at 25°C has a density of 1.40 g/mL. (Assume that the density of pure water remains constant at 1.00g/mL through this temperature range and the volume of the solutions do not change when the salts are added to the water). Calculate the number of grams of salt per 100.0 g of water at each temperature and use the solubility graph to determine the identity of the unknown salt. PINOJ Solubility, solte/100 g water Ba(NO) 20 30 40 80 90 100 50 60 70 Temperature. "C 12. Use the "solubility rules" (Hand Out and/or Table 8.2 in text) to determine and circle the compounds in each set of ionic compounds, that are soluble. Explain your selections. a. PbCl2. Na2CO3, Ag2SO4, KI, LisPO4 rule/reason: b) Zn(NO3)2, AgaCO3, Mg(PO3)2, Hg(NO3)2, PbSO4 rule/reason: c) Ag-CO, Cu(CIO3)2, Hg(CIO)2 CaSO: Pb(ClO3)2 rule/reason: d) BaSO4, PbSO4 Al2(SO4)3 K2SO4 (NH4)2SO4, rule/reason:

Answer 1

11 at 50°C KNO3 density = 1.82g/m -lamo - ова да i loog Ho 82g salt #Only 2 salts are there which have solubility near 82g at 50°c (from graph) These are a Pb(NO3)2 l KNO Pb(NO3)2 80 When solution Cooled to 25 c l unknown salt crystallizes out density = 1. Yog/mL Soleute is nog water Ig. loog ho → 4og solute. #only KNO3 is the salt which has solubility 40g at 250 out of Pb (1103)2 and Kaloz) SO Kaloz Pb(NO3)2 .: Salt is [KNO3] Potassium Nitrate At 5°C 82g 100gho 25 c - Yog/200g H₂O .