PCl5 -----> PCl3 + Cl2 , Kp = 0.0121
0.123 0 0 (at t=0)
0.123-x x x (at equilibrium)
Kp = P(PCl3) * P(Cl2) / P(PCl5)
0.0121 = x * x / (0.123-x)
0.0014883 - 0.0121x = x^2
x^2 + 0.0121x - 0.0014883 = 0
After solving above quadratic equation;
x = 0.0330
Hence,
Pressure of PCl3 at equilibrium = x = 0.033 atm
Answer
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