Calculate the change in internal energy (AU) per mole of H2O2(l) at standard conditions for the...
72. Determine AHº for this reaction from the data below. N2H4(1) + 2 H2O2(1) -→ N2(g) + 4H2O(1) N2H4(1) + O2(g) →→ N2(g) + 2 H2O(1) A Hº = -622.2 kJ mol-1 H2(g) + + O2(g) →→ H2O(1) A Hº = -285.8 kJ mol-1 H2(g) + O2(g) —> H2O2(1) A,Hº = -187.8 kJ mol-1
Again consider the following unbalanced oxidation - reduction reaction: Ba(OH)2(aq) + H2O2(aq) + CIO2(aq) + Ba(CIO2)2(s) + O2(g) Balance this reaction for basic conditions. Once both half reactions are ready to add to give the overall balanced reaction, the number of electrons lost ( = the number of electrons gained) is O 2 O 3 O 1 O none of these
calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l) Given the reactions N2H4(l) + O2(g) -> N2(g) + 2H2O(l) Enthalpy of H = -6.22.2 kJ H2(g) + (1/2)O2(g) -> H2O(l) enthalpy of H = -285.8 kJ/mol H2(g) + O2(g) -> H2O2(l) enthalpy of H = -187.8 kJ
When one mole of gaseous hydrogen peroxide, H2O2, is made from hydrogen and oxygen gases, the enthalpy change is –136 kJ. Which of the following correctly represents the thermochemical equation? i. H2(g) + O2(g) → H2O2(g) + 136 kJ ii. H2(g) + O2(g) + 136 kJ → H2O2(g) iii. H2(g) + O2(g) → H2O2(g) ΔH = –136 kJ iv. H2(g) + O2(g) → H2O2(g) ΔH = +136 kJ A.i only B.ii only C.iii only D.i and iii E.ii and iv
Calculate the value of AHº for the reaction 2 H2O2 (1) + 2 H20 (1) + O2 (9) given the following thermochemical equations: H2(g) + 1/2O2(g) → H2O (1) AH° = -286 kJ H2(g) + O2(g) → H2O2 (1) AH° = - 188 kJ - 196 kJ - 474 kJ + 196 kJ 98 kJ
From the given enthalpies of formation, calculate the enthalpy change for the following reaction. Your label should be in kJ/mol. Again, leave a space between the answer and the label. N2H4(0) + 2H2O2(1) ► N2(g) + 4H2O(1) Thermochemical data: Substance AH(kJ/mol). H2O(1) -285.8 N Hall) 50.7 H2O2(1) -187.8 Answer:
Calculate the change in Gibbs free energy at standard conditions (TSS) and the equilibrium constant for each of the following reactions. (a) CH4(g) + H2O(g) equilibrium reaction arrow CO(g) + 3 H2(g); ?H° = +205.9 kJ, ?S° = +214.7 J/K ?G° 141.9 Correct: Your answer is correct. kJ K (b) CaCO3(s) equilibrium reaction arrow CaO(s) + CO2(g); ?H° = +179.2 kJ, ?S° = +160.2 J/K ?G° 131.5 Correct: Your answer is correct. kJ K
Calculate Gibbs free energy for this reaction (in kJ): 2 H2O2(l) → 2 H2O(l) + O2(g) what is the answer?
Calculate the standard entropy change for the reaction 2H2(g)+O2(g)?2H2O(l) using the data from the following table: Substance ?H?f (kJ/mol) ?G?f (kJ/mol) S? [J/(K?mol)] H2(g) 0.00 0.00 130.6 O2(g) 0.00 0.00 205.0 H2O(l) -285.8 -237.2 69.90 Express your answer to four significant figures and include the appropriate units. Please show me the steps on how to solve this!!! Thank you!!!
Using Hess's Law to Calculate a Standard Enthalpy of Formation On the Solution Calorimetry Lab Report Form, vou will be asked to calculate a standard enthalpy of formation for magnesium oxide based on your experimental results. Below is an example of how to do this type of calculation. Calculate the standard enthalpy of formation of gaseous diborane (B2H6) using the following thermochemical equations: 4 B(s) + 3 O2(g)-> 2 B2O3(s) 2 H2(g) + O2(g) > 2 H20(0) B2H6(8) +3 O2(g)...