Question

What is the dedication of the left end of the rod relatives to the support at the right end?

What is the deformation of the left end of the rod relative to the support at the right end? P = 10 kips L = 10'-9" Material: A-36 steel Diameter, d = 5/8 in. O a) 0.0121 inches to the right O b) 0.145 inches to the right c) 0.145 inches to the left O d) 0.0362 inches to the right O e) 0.0121 inches to the left f) 0.0362 inches to the left

Answer 1

"Deformation = P L/A E d = 0 . 625 P = 10 kips cut the member like (1) - (1) and draw The Free Body Diagram (F B D) tension = + v e compression = -v e (S l) = P L/A E For A - 36 steel youngls modulus = 29 times 10 ^6 l b/in ^2 l = 10' - 9"" l ft = 12"" = (10 times 12 + 9) = (10 times 12 + 9) = 129"" Therefore S l = 10 times 10 ^3 times 129/pi/4 times (0 . 0625) ^2 times 29 times 10 ^6 = 10 times 10 ^3 times 129 times 4/3 . 14 times (0 . 625 ^2) times 29 times 10 ^6 = 0 . 145 "" rightarrow to the left (Deformation = 0 . 145 "" to the left) C"