Question

Q4 (3096). The T-S diagram on the right is showing 4 internally reversible processes in a refrigeration cycle executed with a refrigerant in closed system. (This is NOT a Carnot cycle) Answer 600-A following parts according to the diagram. Determine T in K a) b) c) (5%) the net-work consumed for each cycle, in kJ, (15%) energy interactions in the form of heat for each process, in kJ (5%) the amount of heat taken from the cold reservoir, and amount of heat discharged to the hot reservoir, in kJ, 50 -3 4ool _ ① :@ S in 9 kJ/K d) (5%) coefficient performance for this refrigeration cycle.

Answer 1

4) Solution bou 600 Soo 400 Qin we, th know that for neversi ble pmocen de: Heat interachion for haat inpudt, sne Q12- ITAS : 400 x (4-6): 4,00x3: 1200 kJ 2-3 3 34(Tas Avea under in 3-4 in ths pmocew b) Heat taken trom cold reservlor 's tho heat with posit·wajn · Heat 4dchanged from het nesavior, Jacut:16soKI

from las of theanodymmics 1-2, 8,2=1200 kJ 12 indica회 work nhut to the system Work, dw 1200 K for -the cycle, -from "first lau, of thonmodnnamic』, met heat interachbn is equal to net work thtrachion sihnifhes work is thi System. d) coetfiuent of reaformonte, cop: Babsorbed - 1200 = 2.67 Win