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How is this NONcompetitive inhibition ? How do I find the Vmax ?

How is this NONcompetitive inhibition ?

How do I find the Vmax ?

How is this NONcompetitive inhibition ? How

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Answer #1

Vmax = k2 [Eo] = 900 s-1 x 0.1nM = 90 nM/s

After the addition of the inhibitor, the effective enzyme concentration is lower and also Vmax is lower (50 nM/s).

The evidence that the inhibition is non competitive is the experimental fact that:

      apparent Km = initial Km

and only Vmax is reduced.

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