Question

Find the value of currents I, and in the circuit shown. What is the power supplied by the source? 12 kn w 1 kN 22 w 388 2.4 k

Answer 1

imke - -Region 1k1' 942 12 V L ake 24K Region- 1 Given that E= 12.00 Reg of region , Ri= 2x8 To = 1.6 kr Reg of region , R₂ = 12+(2.4+R) 12 42-4+66 axy tbx 1. = 3kr .: Rear = kr + 3kr + sku = 12 kur E = 12 v . Current in the circuit , I = € - 5 = 42 m4 = lnde

Now, IKA, regiun , and 8k desistances will have the same current , I, because they are an Series 1., = Ima l Voltage for region , E = IXR2 = 43V = 3V 3v= 2-4 xiz +1.6 xI3 (13 Currend 9n 2-4 kur and 1-6 kur regien O)) 13 = 3 m Now, voltage acrost region 0, E, = 16 x = 12v In parallel, voltage demains the same :- 122 = 12 mA T: 12 = 0.67A power supplied by the source : pa I Rey = TE = (1*12) mW TAP= 12mW