20 fold means 20 times. So, 20 times "what" gives you 600 ml. The "what" is found as follows:
(20)(x) = 600 ml
x = 600ml/20 = 30 ml
It means we require 30 ml of bleach
Answer is 30 ml
You need to make 600 ml of a 20-fold dilution of household bleach. Making this dilution...
QUESTION 4 You carry out a dilution adding 20 ml of solution A and 80 mL of water. This dilution can NOT be expressed as: o 1 in 4 dilution. O 1:4 dilution. 5 fold dilution. having a dilution factor of 5. 1 in 5 dilution.
1. Make a 10 fold serial dilution of a protein to achieve a final concentration of 10ug/ml You are staring from a 10 mg/ml protein stock. Indicate the amount of sample needed (from previous tube) and the amount of H20 needed. Make your calculations for 100μ1 volume. (0.5pts) 10ul 90μ1 H20 10mg/ml lmg/ml
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCI, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make 500.0 mL of a PH = 10.23 solution. Use the Ka of hypochlorous acid found in the chempendix.
What volume of sample, in mL, would be needed to make 2 mL of a 5-fold dilution? (3 significant figures needed)
How would you make a 4 fold dilution of X-gal? What would the concentration of the diluted solution be?
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCI, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make a 500.0 mL solution with a pH of 10.26.
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCI, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make 500 0 mL of a pH = 10.26 solution. Use the Ka of hypochlorous acid found in the chempendix.
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make 500.0 mL of a pH = 10.18 solution. Use the Ka of hypochlorous acid found in the chempendix
This is all of the information given for this problem :/
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCI, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make a 500.0 mL solution with a pH of 9.80. volume: mL < Hint eac The hypochlorite ion, OCl-, is sometimes written as C10-. Its conjugate acid, hypochlorous acid, can be written either...
Can you make up 20 ml of a 1:200 dilution from 2 ml of a 1:40 stock solution? (a) If so, how? If not why not? (b) If not what is the largest volume of a 1:200 you could make?