55.69 joules
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Balanced Equation of combustion of metahne
combustion is exothermic.
Given that Enthalpy change for the combustion of Methane ,
1 mole of Methane gas on combustion liberates 891 j of energy
1 mole of Methane = 16 g
16 g of Methane gas on combustion gives out 891 j of energy.
1 g of Methane gas on combustion liberates how much energy( Enthalpy change)= ?
So, enthalpy change on combustion of 1 g of Methane gas =
= 55.6875 joules.
= 55.69 joules
Entyalpy change on combusiton or burning of 1 g of Methane gas in excess of Oxygen = 55.69 jolues.
= 55.69 J
Consider the following reaction. CH4(g) + 2 O2(g) - CO2(g) + 2 H20(1) AH = -891 kJ Calculate the enthalpy change for each of the following cases. (a) 2.00 g methane is burned in excess oxygen. Гk (b) 2.00 x 103 L methane gas at 743 torr and 25°C is burned in excess oxygen.
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4. In the reaction: CH4 (g) + 2 O2(g) → CO2(g) + 2 H20 (2) the initial concentration of CO2 is 0.000 M, and after 30.0 sec, the concentration of CO2 is 0.670 M. What is the average reaction rate over this time span? A) 2.50 M/s B) 0.0223 M/s C) 0.25 m/s D) 1.1 M/s
4 H2(g) + CO2(g) → CH4(g) + 2 H20(g) AH=-165 kJ a. Is the reaction endothermic or exothermic? exothermic b. How many kJ of heat are released when 5.0 moles of CO2 react with excess H2? 3300 number not words.) c. How many kJ of heat are liberated when 12.9 g of H2 react with excess CO2? 264 (Enter a number not words.) [] Full