Question

Using 20 mM AMP and 0.5 mM alcohol dehydrogenase as stock solutions, calculate how to prepare 1 mL of 12 mM AMP with 0.2 mM alcohol dehydrogenase.

Answer 1

Using,

C1V1 = C2V2

with,

C1 and C2 are initial and final concentration

V1 and V2 are initial volume of stock and final solution volume

we get,

To prepare 1 ml of 12 mM AMP solution

V1 = 12 mM x 1 ml/20 = 0.6 ml

So we take 0.6 ml of 20 mM AMP and dilute to 1 ml

To prepare 1 ml of 0.2 mM alcohol dehydrogenase

V1 = 0.2 mM x 1 ml/0.5 mM = 0.4 ml

So, we take 0.4 ml of 0.5 mM alcohol dehydrogenae and dilte to 1 ml