Question

CONSIDER THE FOLLOWING CODE:
double SumString(string x, int n)
{
      double sum = 0;
      for (int i = 0; i < n; i += 2)
            sum += x.length();
      return sum;
}
/////////////////////////////////////////////////////////
void Question()
{
      string a = "string";
      int num = a.length();
      double total = SumString(a, num);
      cout << "The total is: " << total << endl;
}

Select one:

a. The total is: 14.0

b. The total is: 20.0

c. The total is: 16.0

d. The total is: 18.0

Please explain how you get the answer. thank you

Answer 1

Answer: d. The total is: 18.0

string a = "string";

a string value is "string"

int num value is 6

when we are this method double SumString(string x, int n) x value is "string" and n value is 6

for loop will run up to i value is less than n value.

Inside for loop we are adding the length of string every time.

when i = 0, sum value is 6

When i = 2, sum value is 12

When i = 4 , sum value is 18

When i = 6, loop will terminate ans return the sum value as 18.