Question

24-9,10 Convex Mirror Due in 13 hours, 2 minutes A pink eraser is 23.2 mm tall and 11.6 em in front of (and on the axis of) a convex mirror. The mirror has a focal length whose magnitude is 26.1 cm. (a) Where is the image of the eraser? (Give the magnitude and direction of the image ocation. Submit Answer Tries 0/15 (b) What is the image height and type? Submit Answer Tries 0/15 Post Discussion Send Feedback

is a) in front or behind the mirror is b)virtual and upright or real and inverted

Answer 1

Height of the eraser (object) is h_0 = 23.2 mm focal length of the mirror is f = 26.1cm. (a) we use the formula 1/u + 1/v = 1/f where u be the position of object from the mirror. And v be the position of image from the mirror u = -11.6cm we take all distances with negative sign which is on left side of mirror and with positive sign which is on the right side of mirror. 1/ - 11.6 + 1/v = 1/26.1 1/v = 1/26.1 + 1/11.6 \r\n 1/v = 0.12452 v = 8.03cm or v asymp 8cm positive sign of v shows that image will form behind the mirror. (b) magnification of image is m = -v/u = -8.03/ - 11.6 m = 0.692 positive sign of m shows that image will be upright h_I/h_0 = m h_I = m times h_0 h_I = 0.692 times 23.2 h_I = 16.02mm or h_I asymp 16mm