Question

13. Out of 100 red oaks (Quercus rubra) in a population, the frequency of B allele is 0.45. The other allele at the locus, a recessive allele (b), was expressed in 20 individuals. Determine: 1) observed and expected genotype frequencies, and 2) whether the pop'n is at H-W Equilibrium. a. If you conclude its not in H-W Eq., design a study that would eliminate or confirm one evolutionary mechanisms that may be at work. 14. Challenge Question #1:In a population a locus with 3 alleles showed the following genotypic numbers in a sample; aa=0, ab=0, bb=10, ac=0, bc=35, cc=6. Calculate allele frequencies, and determine the expected genotype frequencies under H-W conditions. Do the genotype frequencies depart from those expected by H-W? What may be going on here if they don't? 15. Challenge Question #1: Can a population with more than 80% heterozgotes for locus be in Hardy-Weinberg equilibrium? Less than 10%? Explain.

question 14 and 15

Answer 1

14. Given

aa = 0

ab =0

bb = 10

ac = 0

bc = 35

cc = 6

No.of a allele in population is 0+0 + 0 = 0

No.of b allele in population is 0+ 10+ 35 = 45

No.of c allele in population is 0+35+6 = 41

Total no.of alleles =0+45+41= 86

Allelic frequency of a is 0 /86= 0

Allelic frequency of b is 45/86= 0.523

Allelic frequency of c is 41/86= 0.476

Genotype frequency

Total no.of genotype 0+0+10+0+35+6= 51

Genotyoe frequency of aa 0/86= 0

Genotype frequency of ab 0/86= 0

Genotype frequency of bb 10/86= 0.196

Genotype frequency of ac 0/86=0

Genotype frequency of bc 35/86= 0.6

Genotype frequency of cc 6/86= 0.117

Hardy and weignberg p+q+r= 1

we got 0.99 so it does not obey HW equaltion.