Question

A lens focal length f=+35cm is located on an optical bench. An object is located 50.0cm in front of the lens. Determine the image position for this system. State whether the image is real or virtual. Upright or inverted. Magnified or demagnified.

Answer 1

use,
1/v + 1/u = 1/f
where,
v is image position
u is object position
u = -50 cm

so,
1/v + 1/(-50) = 1/35
1/v = 1/35 + 1/50
1/v = 17/350
v = 20.6 cm
so,
image distance is 20.6 cm
since, v is positive image is real

since, object in between f and 2*f
so, image will be enlarged and inverted