Sol::
Given data:
F(t) = (0.212 N) sin (2π*f*t)
mass(m)= 6.98 kg,
spring constant(k)= 362 N/m
damping constant = 0.261 kg/s
A)
So as we have frequency
f=(1/2π)√(k/m)
= 0.1591*√(362/6.98)
= 1.15 Hz
B)
Now by using the formula
A_0 = (F_0/b)*√(m/k)
= (0.212/0.261)* √(6.98/362)
= 0.0157 m
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