Question

03 HK#9 Due Nov 30 EGEN 203 Moment of inertia and Friction Homework. Due Nov 30 Problem 5) Please determine the smallest coefficient of static friction at B and E that would permit the tongs to lift the 40-kg block. Neglect the weight of the tongs. 300 200 1200 Dimensions in mmC 600 40 kg 240

Answer 1

sigma Fx = 0: F0A = F0D. sigma Fy = 0: 2(FoA)(2/3.61) = 392.4 F0A = 345.141N. sigma M_c = 0Ex(600) - 196.2(120) -294.3 - 196.2(120) -294.3(1200) -196.2(300) = 0. Ex = 667.08N therefore minimum value of mu s = Ey/Es mu s = 196.2/667.08 = 0.294 mu s = 0.294