Question

Two simple pendulums of equal length l = 0.35 m are suspended from the same pivot. The first bob is drawn back to make a 25° angle with the vertical, while the other one is initially hanging at rest. The first bob is released and allowed to elastically collide with the second bob. If the first bob has a mass of 0.20 kg and the second has a mass of 0.3 kg, how high will the second bob rise above its initial position?

Answer 1

Sol" Call 250 By energy consewation ng 2(1-cos2go) I'my? ve = 291 (1-2025) M = {2x9-81X0-35(1-0.999) - 0.64 35 Ws Just before collusion Just after collision. 0.261 12kg Sorg o.ang O O =0.6435 m/ جو احم 0.2kg 0.3 kg Ru momentum conservation 0.2 XO. 6435 -0.25 +0.3 u But av = 1.287 e- 0.6435 coefficent of restitution speed of separation speed of appoach u-v=0.6435 - El s from egr 0 4 (1) su = 1.287 +1.287 - 2.574 2.574 = 0.5148 m/s 25 8 By energy conservation migh Žmy2 he ,2 -0.0135 m. zg 2x9.81 bob rise above initial position=h= 0.0135 m 2nd