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ECE 3424 Student Name & ID: An npn transistor having 1s = 10-A and B = 100 is connected as follows: The emitter is grounded,

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Given data! -15 А 13 = 100 Is = 10 Vcc =+5v Idc =COMA Rc = 3K 2 a ) Dio de current equation UBE ID Is e Vip - UBE Voltage acr

UBE Тр Vr Is Vse Vr in V, - 26 m mv Cat at room temperature) Given Is = 10-15 A Io Idc =10 MA :: UBE = 26 mux In 10x10-6 no 1

VCE 5V - cima x 3K2) V ce 5v- 3 v Vcd 21 Tv Since Base-emittel forward Junction Bias Collectos - Base Reverse Bias. Junction

RB 4.4013 V 10x106 RB 440.13 K 22 we need RB = 440013K 2 to result conditions. Same in operating

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