Question

Consider the balanced chemical reaction for the complete combustion reaction of cyclopropane gas (C,H): a) What compounds are on the left of the reaction (reactants)? Provide the names in alphabetical order (not the formulas, and don't worry about the stoichiometric coefficients for this part), and write the states of each matter **For example if you have 2 NO, (g), you just write nitrogen dioxide in gas state in state, and in state. b) What compounds are on the right of the reaction (products)? Provide the names in alphabetical order (not the formulas, and don't worry about the stoichiometric coefficients for this part), and write the states of each matter. *For example if you have 2 NO, (a). you just write nitrogen dioxide in gas state in state, and in state c) The molar ratio of CO. H2O is division, for example for 6:2 you write 3 d) By burning 4.2 g of cyclopropane, Provide the whole number after moles of CO2 is produced 汝: F3 F4 FS

Answer 1

Consider the balanced chemical reaction for the complete combustion reaction of cyclopropane gas (C,H): a) What compounds are on the left of the reaction (reactants)? Provide the names in alphabetical order (not the formulas, and don't worry about the stoichiometric coefficients for this part), and write the states of each matter **For example if you have 2 NO, (g), you just write nitrogen dioxide in gas state cyclopropane in gas state, and oxygen in gas state b) What compounds are on the right of the reaction (products)? Provide the names in alphabetical order (not the formulas, and don't worry about the stoichiometric coefficients for this part), example if you have 2 NO, (3), you just write nitrogen dioxide in gas state. and write the states of each matter. ***For carbon dioxide in gas state, and water in gas state c) The molar ratio of Co, H2 division, for example for 6:2 you write 3 d) By burning 4.2 g of cyclopropane, 0.3 moles of CO, is produced O is 1 Provide the whole number after 23 F4 FS

explanation:

complete balanced equation

2C3H6 + 9 O2 ------------------> 6CO2 + 6 H2O

2 moles C3H6 ----------------> 6 moles CO2

0.1 mole C3H6 ---------------> 6 x 0.1 / 2 = 0.3 moles CO2

moles of C3H6 calculate by the formula

moles = mass / molar mass

          = 4.2 / 42

         = 0.1