Exercise 11.27 A metal rod that is 5.00 m long and 0.59 cm2 in cross-sectional area...
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Exercise 11.27 A metal rod that is 5.00 m long and 0.59 cm2 in cross-sectional area is found to stretch 0.25 cm under a tension of 4300 N . |
Part A What is Young's modulus for this metal? Express your answer using two significant figures.
SubmitMy AnswersGive Up Incorrect; Try Again; 3 attempts remaining |
Homework Answers
youngs modulus = stress/strain
given F = 4300N
L = 5m
= 0.25cm =
0.0025m
A = 0.59cm^2 = 0.59x10^-4m^2
Y = 4300*5/0.0025*0.59x10^-4
Y = 1.45x10^11 N/m^2
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Exercise 11.27
A metal rod that is 5.00 m long and 0.59 cm2 in cross-sectional
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