We have the following information from the samples
there are rats in the the high protein content group. the total weight gain of the 10 rats is 1220 gms.
The sample mean weight gain of high protein content group is
grams
The sample variance of the weight gains for high protein sample is
there are rats in the the low protein content group. the total weight gain of the 7 rats is 707 gms.
The sample mean weight gain of low protein content group is
grams
The sample variance of the weight gains for low protein sample is
From the sample information we can see that the mean weight gain for the rats in high protein group is more than the rats in low protein group. But this is only in this sample of size 10 and 7. We want to test if this difference in the mean weight gain is true in the population.
Let be the true values of mean weight gains for the rats in high protein and low protein diets.
We want to test the following hypotheses
The sample sizes are less than 30 and we do not know the population standard deviations. Hence we will use t-test and t statistics to test the hypotheses.
Since we assume that the population variances of weight gains in the 2 groups are not the same, the standard error of the difference between the means is
The hypothesized difference in the means from null hypothesis is
The test statistics is
We have been given the degrees of freedom for t statistics = 13.7
This is a right tail test (The alternative hypothesis has ">"). The p-value is P(T>2.00).
Using excel function =T.DIST.RT(2,13.7), we get a p-value = 0.033
We will reject the null hypothesis if the p-value is less than the significance level.
Let us set the significance level at .
We can see that the p-value is greater than the significance level . Hence we can not reject the null hypothesis.
Let us set the significance level at .
We can see that the p-value is less than the significance level . Hence we reject the null hypothesis.
We can conclude that at
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