Use the adder subtraction of Fig. 4.7 that has the following values of input Mode (M) and data inputs (A) and (B). In each case, determine the values of the outputs S3 S2 S1 S0 and C4.
M A B
0 0111 0110
1 101 1010
1 0000 0001
The adder-subtractor circuit of Fig. 4-7 has the following values for input mode M and data inputs A and B. In each case, determine the values of the outputs: S3 S2 S1 S0 and C4.
M |
A |
B |
|
a. |
0 |
0111 |
0110 |
b. |
1 |
0101 |
1010 |
c. |
1 |
1000 |
0001 |
a) Mode is 0. 4-bit addition operation is performed. So, A(0111) + B(0110) gives 1101. where S3 = 1, S2 = 1, S1 = 0, S0 = 1 and C4 = 0 because there is no carry.
b) Mode is given as 1. So, 4-bit subtraction operation is performed on A and B.
A(0101) - B(1010) = 1) 1011 . where S3 = 1, S2 = 0, S1 = 1, S0 = 1 and C4 = 1 because there is 1 bit borrow. Result in decimal form is -5.
c) Mode is given as 1. So, 4-bit subtraction operation is performed on A and B.
A(1000) - B(0001) = 0111 . where S3 = 0, S2 = 1, S1 = 1, S0 = 1 and C4 = 0 because there is no borrow.
Use the adder subtraction of Fig. 4.7 that has the following values of input Mode (M)...
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