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Assume the following: . . The memory is byte addressable. .. Memory accesses are to 1-byte...
Assume the following about a computer with a cache: .. The memory is byte addressable. •...
Assume the following about a computer with a cache: .. The memory is byte addressable. • Memory accesses are to 1-byte words (not to 4-byte words). .. Addresses are 8 bits wide. .. The cache is 2-way associative cache (E=2), with a 2-byte block size (B=2) and 4 sets (5=4). • The cache contents are as shown below (V="Valid"): Set #Way #0 Way #1 V=1;Tag=0x12; Data = v=1;Tag=0x10; Data = Ox39 0x00 0x26 Ox63 V=1;Tag=0x09; Data = v=1;Tag=0x11; Data =...
) Consider an 8-way associative 64 Kilo Byte cache with 32 byte cache lines. Assume memory...
) Consider an 8-way associative 64 Kilo Byte cache with 32 byte cache lines. Assume memory addresses are 32 bits long. a). Show how a 32-bit address is used to access the cache (show how many bits for Tag, Index and Byte offset). b). Calculate the total number of bits needed for this cache including tag bits, valid bits and data c). Translate the following addresses (in hex) to cache set number, byte number and tag (i) B2FE3053hex (ii) FFFFA04Ehex...
Line 1 Set index 2-way set associative cache Line 0 Tag Valid Byte 0 Byte 1...
Line 1 Set index 2-way set associative cache Line 0 Tag Valid Byte 0 Byte 1 Byte 2 Byte 3 Tag Valid Byte 0 Byte 1 Byte 2 Byte 3 091 86 30 3F 10 000 - 45 1 604FEO 23 38 1 00 BC OB 37 EB 0 OB 0 - 06 0 32 1 12 08 7B AD c 06 78 07 06 05 1 40 67 C2 3B 711 6E 0 911 AO B7 26 2DFO 0...
Let's start with a memory system that is byte addressable and has 14-bit addresses. Now let's...
Let's start with a memory system that is byte addressable and has 14-bit addresses. Now let's add a direct mapped cache that can hold 16 blocks (or has 16 lines) and each block is 4 bytes. The table shoun below details the contents of the cache at a particular point in time. if the valid bit is 1 there is a cache block loaded into the cache with Tag as detailed in the tag column. The columns B0-D3 then show...
Assume the cache can hold 64 kB. Data are transferred between main memory and the cache...
Assume the cache can hold 64 kB. Data are transferred between main memory and the cache in blocks of 4 bytes each. This means that the cache is organized as 16K=2^14 lines of 4 bytes each. The main memory consists of 16 MB, with each byte directly addressable by a 24-bit address (2^24 =16M). Thus, for mapping purposes, we can consider main memory to consist of 4M blocks of 4 bytes each. Please show illustrations too for all work. Part...
A byte-addressable memory system contains four memory modules each of which is 32 bits wide by...
A byte-addressable memory system contains four memory modules each of which is 32 bits wide by 2^28 cells deep. The system employs a 1 MB 2-way set associative cache with 128-byte cache lines. It also uses a 32-bit CPU-to-memory data bus as well as 32-bit physical addresses. Each memory module requires 4 clock cycles to perform either a read or a write operation. a) Assuming that the memory system is low order interleaved, show the proper 32-bit format for physical...
Module 10 Assignment - Direct-mapped Cache Direct-Mapped Cache In this question you're given a 16-byte memory...
Module 10 Assignment - Direct-mapped Cache Direct-Mapped Cache In this question you're given a 16-byte memory segment and an 8-byte cache. Given the following series of memory accesses, complete the table below. Use the first Contents/Tag column to insert an item to the cache the first time and use the second Contents/Tag column if a cache entry is overwritten. Note: no index will have more than two blocks mapped to it. The first two examples have been provided. How many...
18. You have a byte-addressable virtual memory system with a two-entry TLB, a 2-way set associati...
18. You have a byte-addressable virtual memory system with a two-entry TLB, a 2-way set associative cache, and a page table for a process P. Assume cache blocks of 8 bytes and page size of 16 bytes. In the system below, main memory is divided into blocks, where each block is represented by a letter. Two blocks equal one frame. Given the system state as depicted above, answer the following questions: a) How many bits are in a virtual address...
3. 12+2-4 points] We are comparing the two caches in Problem 1 and Problem 2. Suppose both caphes have a hit time of 2 cycles. The cache in Problem 1 has a miss penalty of 15 cycles. The o...
3. 12+2-4 points] We are comparing the two caches in Problem 1 and Problem 2. Suppose both caphes have a hit time of 2 cycles. The cache in Problem 1 has a miss penalty of 15 cycles. The one in Problem 2 has a miss penalty of 25 cycles. Calculate the total time taken (in cycles) for all accesses, for each cache. Which cache is better- the one in Problem 1 or Problem 2? 3. 12+2-4 points] We are comparing...
Consider the following code. Assume that the array begins at memory address Ox200. What is printed...
Consider the following code. Assume that the array begins at memory address Ox200. What is printed by the following code. Assume sizeof(int) is 4 bytes and sizeof(char) is 1 byte. Do not include the Ox or leading zeros in your answer. Enter -1 if the answer is indeterminate, or -2 if the code generates a compile error, or -3 if the code generates a runtime error. #include <stdio.h> int main() { int a[] {1,2,3}; int *iptr a; printf("%p\n", iptr+1); return...
Assume the following about a computer with a cache: .. The memory is byte addressable. • Memory accesses are to 1-byte words (not to 4-byte words). .. Addresses are 8 bits wide. .. The cache is 2-way associative cache (E=2), with a 2-byte block size (B=2) and 4 sets (5=4). • The cache contents are as shown below (V="Valid"): Set #Way #0 Way #1 V=1;Tag=0x12; Data = v=1;Tag=0x10; Data = Ox39 0x00 0x26 Ox63 V=1;Tag=0x09; Data = v=1;Tag=0x11; Data =...
Line 1 Set index 2-way set associative cache Line 0 Tag Valid Byte 0 Byte 1 Byte 2 Byte 3 Tag Valid Byte 0 Byte 1 Byte 2 Byte 3 091 86 30 3F 10 000 - 45 1 604FEO 23 38 1 00 BC OB 37 EB 0 OB 0 - 06 0 32 1 12 08 7B AD c 06 78 07 06 05 1 40 67 C2 3B 711 6E 0 911 AO B7 26 2DFO 0...
Let's start with a memory system that is byte addressable and has 14-bit addresses. Now let's add a direct mapped cache that can hold 16 blocks (or has 16 lines) and each block is 4 bytes. The table shoun below details the contents of the cache at a particular point in time. if the valid bit is 1 there is a cache block loaded into the cache with Tag as detailed in the tag column. The columns B0-D3 then show...
Module 10 Assignment - Direct-mapped Cache Direct-Mapped Cache In this question you're given a 16-byte memory segment and an 8-byte cache. Given the following series of memory accesses, complete the table below. Use the first Contents/Tag column to insert an item to the cache the first time and use the second Contents/Tag column if a cache entry is overwritten. Note: no index will have more than two blocks mapped to it. The first two examples have been provided. How many...
18. You have a byte-addressable virtual memory system with a two-entry TLB, a 2-way set associative cache, and a page table for a process P. Assume cache blocks of 8 bytes and page size of 16 bytes. In the system below, main memory is divided into blocks, where each block is represented by a letter. Two blocks equal one frame. Given the system state as depicted above, answer the following questions: a) How many bits are in a virtual address...
3. 12+2-4 points] We are comparing the two caches in Problem 1 and Problem 2. Suppose both caphes have a hit time of 2 cycles. The cache in Problem 1 has a miss penalty of 15 cycles. The one in Problem 2 has a miss penalty of 25 cycles. Calculate the total time taken (in cycles) for all accesses, for each cache. Which cache is better- the one in Problem 1 or Problem 2? 3. 12+2-4 points] We are comparing...
Consider the following code. Assume that the array begins at memory address Ox200. What is printed by the following code. Assume sizeof(int) is 4 bytes and sizeof(char) is 1 byte. Do not include the Ox or leading zeros in your answer. Enter -1 if the answer is indeterminate, or -2 if the code generates a compile error, or -3 if the code generates a runtime error. #include <stdio.h> int main() { int a[] {1,2,3}; int *iptr a; printf("%p\n", iptr+1); return...
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