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The time to failure (in hours) of fans in a personal computer can be modeled by...
QUESTION 6 The time to failure (in hours) of fans in a personal computer can be...
QUESTION 6 The time to failure (in hours) of fans in a personal computer can be modeled by an exponential distribution with rate 0.0005. Round your answers to 4 decimal places. (a) What proportion of fans will last at least 10000 hours? (b) What proportion of fans will last at most 8000 hours? QUESTION 7 Given the probability density function f(x)=(0.02^9 x^8*e^(-0.02x))/8! for x>0 and f(x)=0 otherwise. Determine the mean and variance of the distribution. Round the answers to the...
The compressive strength of samples of cement can be modeled by a normal distribution with a mean of 6000 kilograms per...
The compressive strength of samples of cement can be modeled by a normal distribution with a mean of 6000 kilograms per square centimeter and a standar deviation of 100 kilograms per square centimeter c) what strength is exceeded by 95% of the samples? The life of a semiconductor laser at a constant power is normally distributed with a mean of 7000 hours and a standar deviation of 600 hours a) what is the probability that a laser fails before 5000...
3. The time to failure (Y , measured in hours) of fans in a laptop computer...
3. The time to failure (Y , measured in hours) of fans in a laptop computer is modeled using an exponential distribution with λ = 0.0002. (a) Graph the pdf of Y . Compute E(Y ) and var(Y ). Place an “×” on the pdf indicating where E(Y ) is. (b) What is the probability that a fan will fail before 6,000 hours? will survive at least 12,000 hours? (c) Only 1 percent of all fans’ lifetimes will exceed which...
Suppose that the time to failure (in hours) of hard drives in a personal computer can...
Suppose that the time to failure (in hours) of hard drives in a personal computer can be modelled by an exponential distribution with λ = 0.003. Use Monte Carlo simulation, or otherwise, to approximate the following: Assume a computer now has 4 independent hard-drives and the failure of the computer occurs once all 4 hard drives have died. What is the mean life of the computer?
FULL SCREEN PRINTER VERSION BACK NEXT Question 14 The time to failure (in hours) for a...
FULL SCREEN PRINTER VERSION BACK NEXT Question 14 The time to failure (in hours) for a laser in a cytometry machine is modeled by an exponential distribution with 1 0 .00004. Round the answers to 3 decimal places. (a) What is the probability that the laser will last at least 20028 hours? (b) What is the probability that the laser will last at most 30375 hours? (c) What is the probability that the laser will last between 20028 and 30375...
The mean time to failure for a circulation pump is 1000 hours and the time to...
The mean time to failure for a circulation pump is 1000 hours and the time to failure has an exponential distribution. If the pump has already been operating 600 hours, what is the probability that it will fail within the next 1400 hours? State your answer rounded to three decimal places.
The demand for ceiling fans can be modeled below as D(p) 25.52(0.996P) thousand ceiling fans where p is the price (in dollars) of a ceiling fan (a) According to the model, is there a price above whic...
The demand for ceiling fans can be modeled below as D(p) 25.52(0.996P) thousand ceiling fans where p is the price (in dollars) of a ceiling fan (a) According to the model, is there a price above which consumers will no longer purchase fans? Explain why or why not. ▼ the horizontal axis. Therefore there l above which consumers will not purchase a ceiling fan The model is exponential and ' Select-- -Select- (b) Calculate the amount that consumers are willing...
Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull distribution...
Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull distribution with B 0.5 and = 3400. Determine the following in parts (a) and (b) Round your answers to three decimal places (e.g. 98.765) a) P(X> 3500) = i b) P(X> 6000|X > 3000) i c) Suppose that X has an exponential distribution with mean equal to 3400. Determine the following probability Round your answer to three decimal places (e.g. 98.765) P(X 6000X > 3000)...
. Suppose the time until failure (in years) of a laptop computer follows an exponential distribution...
. Suppose the time until failure (in years) of a laptop computer follows an exponential distribution with a mean life of 6 years. a) What is the median life of a laptop computer (in years)? b) What is the probability that a laptop computer will last more than 6 years?
Statistics - Please help! Thanks. 5. Let X be the random variable that describes the measurements...
Statistics - Please help! Thanks.
5. Let X be the random variable that describes the measurements of the diameter of Venus. We know that X is normally distributed with mean u = 7848 miles and standard deviation o = 310 miles. What is (a) P(x < 7000) (b) P(8000< x < 8100) (c) Verify your answers using R. 6. Assume the life of a roller bearing follows a Weibull distribution with parameters ß = 2 and 8 = 7,500 hours....
QUESTION 6 The time to failure (in hours) of fans in a personal computer can be modeled by an exponential distribution with rate 0.0005. Round your answers to 4 decimal places. (a) What proportion of fans will last at least 10000 hours? (b) What proportion of fans will last at most 8000 hours? QUESTION 7 Given the probability density function f(x)=(0.02^9 x^8*e^(-0.02x))/8! for x>0 and f(x)=0 otherwise. Determine the mean and variance of the distribution. Round the answers to the...
FULL SCREEN PRINTER VERSION BACK NEXT Question 14 The time to failure (in hours) for a laser in a cytometry machine is modeled by an exponential distribution with 1 0 .00004. Round the answers to 3 decimal places. (a) What is the probability that the laser will last at least 20028 hours? (b) What is the probability that the laser will last at most 30375 hours? (c) What is the probability that the laser will last between 20028 and 30375...
The demand for ceiling fans can be modeled below as D(p) 25.52(0.996P) thousand ceiling fans where p is the price (in dollars) of a ceiling fan (a) According to the model, is there a price above which consumers will no longer purchase fans? Explain why or why not. ▼ the horizontal axis. Therefore there l above which consumers will not purchase a ceiling fan The model is exponential and ' Select-- -Select- (b) Calculate the amount that consumers are willing...
Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull distribution with B 0.5 and = 3400. Determine the following in parts (a) and (b) Round your answers to three decimal places (e.g. 98.765) a) P(X> 3500) = i b) P(X> 6000|X > 3000) i c) Suppose that X has an exponential distribution with mean equal to 3400. Determine the following probability Round your answer to three decimal places (e.g. 98.765) P(X 6000X > 3000)...
Statistics - Please help! Thanks.
5. Let X be the random variable that describes the measurements of the diameter of Venus. We know that X is normally distributed with mean u = 7848 miles and standard deviation o = 310 miles. What is (a) P(x < 7000) (b) P(8000< x < 8100) (c) Verify your answers using R. 6. Assume the life of a roller bearing follows a Weibull distribution with parameters ß = 2 and 8 = 7,500 hours....
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