Question

ha way th equivalent resistance of the netw makes the parallel and series combinations clearer.] 35. In the circuit shown below a) find the equivalent resistance of the network of resistors; b) find the current through the battery; c) find the current through the 2- resistor. Explain your reasoning. 2Ω 10 Ω 18 V 12 Ω 40 40 40 8Ω ww Ww ww

Answer 1

solution > (9) ar and 4 on in last row are in series with equivalent 62 This ar į in parallel with 12 r to equivalent resistance of brand = R = 6X12 =42 6 +12 R = 4 r and or are inseries and equal to l22 Also 4,02 and ur are in paralled and equal to a single resistance al 22 lor ton = 12.8 so There are two 12 r resistance in Parallel so the equivalent resistance of the cereait = Req= 62 Req = 6 or 16) Cerrent = I= 23.0 A [ 310 310 A (c) current through our resistance =li0oA. And, the current through 12 r resistance = ous A similar lay current through to s resistance - list such that Total carrent=300A T 1.00 JA