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I dont understand wh35 kPa and 8-37 Water vapor enters a compressor at 160°C, and leaves at 300 kPa with the same specific entropy as at the inlet. What is the temperature and the specific enthalpy of water at the compressor exit? cQ Search the web.. C Solved: Stei C Chegg Stuc C How Woulc C Chegg Stuc C Introductio C An Activate C 35 KPa X > O 仚 凸https://www.chegg.com/homework-help/questions-and-answers/35-kpa-8ー37-water-vapor-enters-com EChegg Study Search TEXTBOOK SOLUTIONS EXPERT Q&A Was this answer helpful? 651 answers Using Table A-4 (Superheated water vapor); At P1 35 kPa 0.035 MPa and T1 160°C; s18.1519 kJ/kg.K It is given that the entropy remains constant. Hence 2-s1-8.1519 kJ/kg.K Now, using Table A-4 (Superheated water vapor); At P2 300 kPa 0.300 MPa and s2 8.1519 kJ/kg.K; s.1519 8.0330 (440 400) 8.1538 -8.0330 T2400+ 101)( 8.1519 -8.0330 8.1538 -8.0330 (3358.7 - 3275) h2-3357.384 kJ/kg ANSWERS: T2 439.37°C h2-3357.384 k.J/kg Comment>ere are these values are coming from. I cant find them in the tables.

S=8.1519?

S=8.0330?

S=8.1538?

400

440

Idont understand how the problem was solved.

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