Question

Need both answered please!

1. A particle moves with acceleration function a(t) = 8t + 5. Its initial velocity is v(O) = -4 cm/s and its initial displacement is s(0) = 5. Find its position after t seconds. s 2. The equation of motion of a particle is S = t3 - 9t, where s in meters, and t is in seconds. Find a) The velocity and acceleration as a function oft b) The acceleration after 4 seconds.

Answer 1

o alt) = 84+5 VCO) = -4cmis Sco2 = 5 vit)=falt) dt = 8t² +5ftc Ult) = 44245t to VCO) = -4 cm's Questo6acco -4 54100+500)+c ) 1(-4 $(t) VE)=442 +54 -4 =s Vet) dot = strt2+54 4) dot s(t) = 4x2+542-46+C SPO) = 5 = 0 to Otc )(=5

=> $(t) = 403 +55 -44 +5) position after & seconds | # s=43-9t, @ velocitafu) = loristimo Tu=38-9 velocity w Get acceleration - alt) = du = Tat)= at 4 second acceleration after criven 1. =) alt] =64 t=4 --) 914)=614) 204)24 7