Homework Answers
Solution:
(19)
Given,
=>Number of general-purpose register = 15
=>Size of each register = 32 bit
The answer will be an option,
(4) 4
Explanation:
=>There are 15 registers so the number of bits required to represent these 15 registers = ceil(log2(15)) bits
=>Number of bits required = ceil(3.9068) bits
=>Number of bits required = 4 bits
=>So 4 bits must be reserved in the machine code instruction in order to address any of these fifteen registers.
I have explained each and every part with the help of statements attached to it.
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