Question

Please help me with question 2 ASAP

Question 1 [15 Marks A 500-kV, 60-Hz, 3-phase completely transposed overhead line has the resistance R=0.0201/km, Ds = 0.149m and r=0.16m. The horizontal phase spacings between the conductors are 10, 10, and 20 m. Calculate a) the line inductive reactance in /km, b) the line impedance in /km, c) the line capacitance-to-neutral Can in F/m, d) the admittance-to-neutral in S/km, neglecting the effect of the earth plane, and e) the exact ABCD parameters of the line when its length is 300 km.

Answer 1

Conductors 3-6 horisontal 3-8 d=com * da con spacing, d=2ou Fay 34 Houdoutai Conductor configugation 43 Lyph . 0.2 len 2d Y -0.16m and rl = 0.7788 0.124.

- 0.2 l 21.10 0.124 Liph 20.924 milan given langth ly = 180kr. 0-924 XBO 166.35 mi Xulph = 27f Lpn - 52 263 2 R=0.0201 fins 3.618 r p=tan(x/a) 121= Serrixe 121 = 86.530. -'.2 : 52-36 86-58 52-38 2 2= 3.185+j52-532. Now 21 Eo Cph 20E by 23. 10 0.14 nosan 1.274 102 nE c/ph = 1.214 X 102 x180 nF 2.29 nE Y = /G + jxe

in nominal al model) Y = ů 2.29 x 10 9 given length Cl = 180 → Based the llue 2.5.180 bar), It is a Mediu Transuission line & Assuna the given line ... A B C D parametegls are B=2 A =D = 1+ YZ c. Y (1 72 ) given PR= 1600mw , VR = 475 tu, Cosp=0.95 PR Valph 475 Simb PB VR coser 3274-21 Sino 2047.11 A 2047.11 (0.95-80.312) = 1944.15=1639.21 A XLI IR R IL pe Icra z 2 Vs F% → T-model fig-1

from figni y = Jat Is Ich ŽYve Ź (0+ 3329301) (274-21 x10") C3 2.139x104 . .. 1944.75 -3639-21 + 13-137 X109 1944.15-1639.2 als = VR + I2 (274-21X109) +((qu4.15-j634. 23:57 35283) 313.884 tj 100 kv. - ولا 329.56317.66 kV and It Ice Jer = ŽY V 16+32 248161) (34-404 + jas) i 8 (-1.446+j3:595-)104 A Is = 1944.15-j 639-2-1-1464 13-595 A 1944.74 - J639.19 2047.10 L-18-19 A Is =

3 % 224.563 X 10% 20470 - 31N1I sending and power PS 2023.94 MW Sanding gend power factory Coops = cos (Vs^ I) (17.68 - (-18-19)) Corps 0.81 lag Cos full load line loss Ps-PR = 423.94 MW. .). New band - x Loo Ps 19.05.). A=D= It Y2 2 A =D NI B = 2 = 3.1185 tj 52-532 = 52.38 186.13 czy (1+ y2) ~ 12.29869 V = AVA + BIR Is = CAR + D.IR At no-loud TR=0 VRO-Us Xio ./. 4. Reg :: AURO VS avro