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c) For the circuit shown in Figure 3, where u(t) is the unit step function, using Laplace transform methods and showing all w

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LH + 6+ 7e uta 4) 5.2 ilt Ult) Laplace transform sta 2[ze btult) St6 - R L[R] => L [. SL ekt becomes A LS mm 13 * YOS 5 3 7 S3 in sub 7 ics) - st6 4C 312) ics 35 4 {(8+2xsto) now ret + St2 sto (5+2756) ACS+6) + B (St 2) 27 i (6+2 st) (5.2) (st6 ACS+6becomes 35 + sta stb. { cs) 55+ [atz sto] med stor sto] - ics) 5 E apply inverse laplace transform on earl kav ieves) ma S (m

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