If 13.2 kg C3He is completely combusted, what is AHan? 2. Find dHnn for C (s)...

Question

Question

If 13.2 kg C3He is completely combusted, what is AHan? 2. Find dHnn for C (s) + H2O (g) → CO (g) + H2 (g) given: C + O2 → CO2 dHnn =-393.5 kJ Hun =-566.0 kJ Hun =-483.6 kJ 2H2 + O2 → 2H2O

science chemistry

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

1.

13.2 kg = 13200 gm

molar mass of C₃H₈ = 44.1 gm/mole

According to reaction 1 mole of C₃H₈ $\Delta$ H_rxn = -2044 KJ

that mean for 44.1 gm C₃H₈ $\Delta$ H_rxn = -2044 KJ

then for 13200 gm of C₃H₈ $\Delta$ H_rxn = -2044 X 13200 / 44.1 = -611809.5 KJ

if 13.2 Kg C₃H₈ completly combusted then $\Delta$ H_rxn = -611809.5 KJ

Add a comment

Answer 2

Similar Homework Help Questions

Part A Calculate Δ Han for the following reaction: C(s) +H2O(g)CO(g)+H2() Use the following reactions and...

Part A Calculate Δ Han for the following reaction: C(s) +H2O(g)CO(g)+H2() Use the following reactions and given ΔΗ values: C(s) + O2 (g)- CO2 (g), ΔΗ-393.5 kJ 2CO (g) + O2 (g)--2CO2 (g), ΔΗ-566.0 kJ 2H2 (g) +02 (g)-2H3O(g). Ан :-483.6 kJ Express your answer using four significant figures. kJ Submit Request Answer
Find ∆H◦ of the reaction 2C2H2(g) + 5O2(g) = 4CO2(g) + 2H2O(g), as it is written,...

Find ∆H◦ of the reaction 2C2H2(g) + 5O2(g) = 4CO2(g) + 2H2O(g), as it is written, given the following: 2C(s) + H2(g) = C2H2(g), ∆H◦ = +227.4 kJ, 2H2(g) + O2(g) = 2H2O(g), ∆H◦ = −483.6 kJ, C(s) + O2(g) = CO2(g), ∆H◦ = −393.5 kJ.
C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values...

C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values for reactions at 25°C, what is AH at 25°C for the following reaction: C3H3(g) + 502(g) + 4H2O(g) + 3CO2(g) AH = -2043 kJ 3C(s) + 4 H2(g) → C3H8 (g) 2H2(g) + O2(g) + 2H2O(g) AH° = -483.6 kJ

8. Find ∆H◦ of the reaction 2C2H6(g) + 7O2(g) = 4CO2(g) + 6H2O(g), as it is...

8. Find ∆H◦ of the reaction 2C2H6(g) + 7O2(g) = 4CO2(g) + 6H2O(g), as it is written, given the following: 2C(s) + 3H2(g) = C2H6(g), ∆H◦ = −84.68 kJ, 2H2(g) + O2(g) = 2H2O(g), ∆H◦ = −483.6 kJ, C(s) + O2(g) = CO2(g), ∆H◦ = −393.5 kJ. (A) −3194 kJ (B) −3109 kJ (C) −2940 kJ (D) −2855 kJ (E) −1428 kJ
Consider the following data. 2 C(s) + H2(g) C2H2(g) H = +226.8 kJ CO2(g) C(s) +...

Consider the following data. 2 C(s) + H2(g) C2H2(g) H = +226.8 kJ CO2(g) C(s) + O2(g) H = +393.5 kJ 2 H2O(l) 2 H2(g) + O2(g) H = +571.7 kJ Use Hess's law to calculate H for the reaction below. 2 C2H2(g) + 5 O2(g) 4 CO2(g) + 2 H2O(l) find kJ
Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l)....

Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l). Use the series of reaction that follows: 1. C(s)+2H2(g)-> CH4(g), delta H= -74.8 kJ 2. C(s)+O2(g)->CO2(g), delta H= -393.5 kJ 3. 2H2(g)+O2(g)-> 2H2O(g), delta H= -484.0 kJ 4. H2O(l)->H2O(g), delta H= 44.0 kJ

Calculate the enthalpy of the following reaction: C (s) + 2 H2 (g) --> CH4 (g)...

Calculate the enthalpy of the following reaction: C (s) + 2 H2 (g) --> CH4 (g) Given: C (s) + O2 (g) --> CO2 ΔH = -393 kJ H2 + 1⁄2O2 --> H2O. ΔH = -286 kJ CH4 + 2O2 --> CO2 + 2H2O ΔH = -892 kJ
Consider the following data. CH4(g) C(s) + 2 H2(g) H = +74.8 kJ C(s) + O2(g) CO2(g) H = -393.5 kJ 2 H2(g) +...

Consider the following data. CH4(g) C(s) + 2 H2(g) H = +74.8 kJ C(s) + O2(g) CO2(g) H = -393.5 kJ 2 H2(g) + O2(g) 2 H2O(l) H = -571.7 kJ Use Hess's law to calculate H for the reaction below. CH4(g) + 2 O2(g) CO2(g) + 2 H2O(l) H = _____ kJ
Question 6 1.5 pts Predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any,...

Question 6 1.5 pts Predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the following reactions will be spontaneous. A. 2CO(g) + O2(g) = 2002(g), AH rxn=-566.0 kJ [ Select] B. 2NO2(g)2NO(g)+O2(g), AH rxn= +113.1 kJ [ Select ] C. 2H2(g)+O2(g)—2H2O(g), AH rxn=-483.6 kJ [ Select] D. 2H2O2(1)→2H2O(1)+O2(g), AH rxn= -196.0 kJ [Select ]

6. Calculate AH Reaction for the Reaction: N2H4 + 2N2O5 + 2HNO3 + 2NO2 + 2...

6. Calculate AH Reaction for the Reaction: N2H4 + 2N2O5 + 2HNO3 + 2NO2 + 2 NH Using the following equations: H2 + 2N2 + 5022HNO3 + 2NO2 N2H4 + 2NH + H2 2N205 2N2 + 502 AH = -202 kJ AH = +567 kJ AH = +22.6 kJ 7. Calculate the AHReaction for the reaction 2H2(g) + CO(g) → CH3OH(1) Using the following equations: CH3OH() + O2(g) → C(s) + 2H2O() C(s) + 02 (9) — CO(g) H2(g) +...

If 13.2 kg C3He is completely combusted, what is AHan? 2. Find dHnn for C (s)...

Homework Answers

Add Answer to:
If 13.2 kg C3He is completely combusted, what is AHan? 2. Find dHnn for C (s)...

Post as a guest

Earn Coins

Part A Calculate Δ Han for the following reaction: C(s) +H2O(g)CO(g)+H2() Use the following reactions and...

Find ∆H◦ of the reaction 2C2H2(g) + 5O2(g) = 4CO2(g) + 2H2O(g), as it is written,...

C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values...

8. Find ∆H◦ of the reaction 2C2H6(g) + 7O2(g) = 4CO2(g) + 6H2O(g), as it is...

Consider the following data. 2 C(s) + H2(g) C2H2(g) H = +226.8 kJ CO2(g) C(s) +...

Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l)....

Calculate the enthalpy of the following reaction: C (s) + 2 H2 (g) --> CH4 (g)...

Consider the following data. CH4(g) C(s) + 2 H2(g) H = +74.8 kJ C(s) + O2(g) CO2(g) H = -393.5 kJ 2 H2(g) +...

Question 6 1.5 pts Predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any,...

6. Calculate AH Reaction for the Reaction: N2H4 + 2N2O5 + 2HNO3 + 2NO2 + 2...

If 13.2 kg C3He is completely combusted, what is AHan? 2. Find dHnn for C (s)...

Homework Answers

Add Answer to: If 13.2 kg C3He is completely combusted, what is AHan? 2. Find dHnn for C (s)...

Post as a guest

Earn Coins

Add Answer to:
If 13.2 kg C3He is completely combusted, what is AHan? 2. Find dHnn for C (s)...