A1) The volume of the cylinder is
V = ?h(d/2)2
where h = average height of the cylinder and d = average diameter of the cylinder. Plug in values and get
V = 3.14*(2.14 cm)*(1.27 cm/2)2 = 3.14*(2.14 cm)*(0.635 cm)2 = 2.70951 cm3.
The density of the cylinder is
d = M/V
where M = average mass of the cylinder. Plug in values and get
d = (20.76 g)/(2.70951 cm3) = 7.6619 g/cm3 ? 7.66 g/cm3 (ans).
A2) We know that
1 ounce = 28.3495 g.
1 inch = 2.54 cm.
Therefore, (1 inch)3 = 1 inch3 = (2.54 cm)3 = 16.38706 cm3.
The density of the cylinder is 7.66 g/cm3.
The volume of the cylinder is given as
V = M/d
Plug in values and obtain
V = (29.2 ounce)*(28.3495 g/1 ounce)/(7.66 gcm3) = 108.06895 cm3 = (108.06895 cm3)*(1 in3/16.38706 cm3) = 6.594773 in3 ? 6.59 in3 (ans).
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Error Propagation and Density of Materials
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work
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alcohol column. With math shown and included please! The question
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percent error's (with work shown) of the water and isopropyl
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