Question

use impusle momentum please 14.93 A 10-kg block B is suspended by a cord that passes around a pulley at D and is wrapped around the drum of a 100-kg wheel as shown. The wheel with the drum has a central radius of gyration k = 0.5 m and the system is released from rest. If the wheel rolls without slipping, determine V, of block B when it is 2 s after the release. 0.8 mt -0.6 m 100 kg 10 kg B P14.93 correct repsonse is: 3.54 m/s downward

Answer 1

-0.6m, 981N bloky Solution in P: (09): 98.10. (14.43) Mass of Block-B = mg = 10 ty Mars of the chun = M = look. 0.8m, a rooly | J, Podgja Radius of gyration of down z R = 0.5m, - Given system is released from rest. Need to determine velocity of Block B NB Figure o when it in 2 sec after release. Moment of inertia of drun = 5: MR2 = (100) (0-5) = 25 kg.m?. The tension in the rope due to weight of Block B = PE 98.10 Let the angulos velocity of drum = w. Rutates without slipping at in given the drum. wheel work energy to the above & System, Applying principle of (P)(0.8) = 2 aw2 =) (98-1)(0.8)= 6) (25)(w) w: 2.5057 red free. Angular velocity of Souma Now Applying Empulse momentum equation to the above system (P)(t) = (M) ( vg - Vi] (98.1)[2) = (100) [vo- & sus7 X06)] .: VB = 3.517 mhace when it in 2 sec after the release = Vo: 3.519 were ... velouty of block B