Question

IL 275 (3 marks) Q2 Eyring equation in term of concentration can be written as sta ky (9)3-18 where n=1 or 2 Given: E=AH + 2
0 0
Add a comment Improve this question Transcribed image text
Answer #1


1-n K UT (no) agt RT For bimolecular reactim n=2. of KI KI ((1-2) e RT 4G* = SH* _TASE 4H a 54 Kr UT CO (-1) e BT I R h + AHunit of (LT) (5) unit of kr - sy So the order of the reaction is as the unit of Us is 5! 1st order Rr with Arrhenius Compare

Add a comment
Know the answer?
Add Answer to:
IL 275 (3 marks) Q2 Eyring equation in term of concentration can be written as sta...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Homework As in the lecture note, the three expressions for the bimolecular reaction rate constant are:...

    Homework As in the lecture note, the three expressions for the bimolecular reaction rate constant are: Collision theory: 1/2 87k k = P(r = P(53 +rs)? ( Brak 3 ?) " 2-8"RT (1 + r)2 + r.)2 e-E/RT Transition state theory: k2 = kRT e-AG*/RT _ B Fe 4S*/Re-AH*/RT hcoe45 Arrhenius: k = Ae-Ea/RT If we define the Arrhenius A factor as a temperature-independent coefficient, what is A corresponding to in collisional theory and in transition state theory?

  • Learning Goal: To use the Arrhenius equation to calculate the activation energy. As temperature rises, the...

    Learning Goal: To use the Arrhenius equation to calculate the activation energy. As temperature rises, the average kinetic energy of molecules increases. In a chemical reaction, this means that a higher percentage of the molecules possess the required activation energy, and the reaction goes faster. This relationship is shown by the Arrhenius equation k=Ae−Ea/RT where k is the rate constant, A is the frequency factor, Ea is the activation energy, R = 8.3145 J/(K⋅mol) is the gas constant, and T...

  • 21C.1(a) The reaction of propylxanthate ion in acetic acid buffer solutions has the mechanism A− +H+→P....

    21C.1(a) The reaction of propylxanthate ion in acetic acid buffer solutions has the mechanism A− +H+→P. Near 30 °C the rate constant is given by the empirical expression kr=(2.05×1013) e−(8681K)/T dm3mol−1 s−1. Evaluate the energy and entropy of activation at 30 °C. 21C.1(b) The reaction A− +H+→P has a rate constant given by the empirical expression kr=(6.92×1012)e−(5925K)/T dm3mol−1 s−1. Evaluate the energy and entropy of activation at 25 °C. Please explain why they calculated H=E-RT like that like why is...

  • 7. Using the following reaction progress diagram, answer the questions below: wiring Energy A G Rxn....

    7. Using the following reaction progress diagram, answer the questions below: wiring Energy A G Rxn. a. How many steps are in the reaction? How do you know? (4 points) b. Which letter corresponds to the rate-determining-step? Explain your choice. (6 points) c. Is the reaction exothermic or endothermic? How do you know? (4 points) d. If the energy at point B is lowered, what will happen to the rate of the reaction will it increase, decrease, or stay the...

  • help!! (CH3),CBr + 1 → (CH3),CI + Br the following data were collected: [(CH3)3Br] (M) Time...

    help!! (CH3),CBr + 1 → (CH3),CI + Br the following data were collected: [(CH3)3Br] (M) Time (s) 0.600 0 0.424 10.0 0.300 20.0 0.212 30.0 0.150 40.0 Determine the rate law for this reaction and calculate the rate constant. (20 points) E (V) Thermodynamics: AGº - AH-TAS Nernst Equation: 8 = 8°-(RT/nF)InQ AGⓇ--RTINK At 25°C: 8-6° -0.0591/n)logQ AG RT K-e AG° = -nF8° Units/Constants: Volt: 1 V-1 JC Faraday: 1 F -96,485 C/mole Ea/RT Arrhenius Equation: k = Ae R-8.314...

  • 5. How much faster would a reaction be if a catalyst is used that lowers the...

    5. How much faster would a reaction be if a catalyst is used that lowers the activation energy from 20.0 kJ/mol to 10.0 kJ/mol? Do the calculation at two temperatures: first at 25.0°C and then at 0.0°C. (20 points) (V) Helpful Stuff Thermodynamics: AG° = AH-TAS Nernst Equation: 6 = 6 - (RT/nF)InQ AG=RTIK At 25°C: 8 = 6 - (0.0591/n)logQ AGRT Ke=e AGⓇ =-nF8° Units/Constants: Volt: 1 V = 1 J/C Faraday: 1 F = 96,485 C/mole Arrhenius Equation:...

  • 2. Using the decay chain for 238U, calculate the amount of time it takes 5.0 kg...

    2. Using the decay chain for 238U, calculate the amount of time it takes 5.0 kg of 238U to decay to 2.5 kg. What mass of 206Pb is produced? (5 points) (V) Helpful Stuff Thermodynamics: AG° = AH-TAS Nernst Equation: 6 = 6 - (RT/nF)InQ AG=RTIK At 25°C: 8 = 6 - (0.0591/n)logQ ΔGIRT Ke=e AGⓇ = -nF8° Units/Constants: Volt: 1 V=1/C Faraday: 1 F -96,485 C/mol e Arrhenius Equation: k = Ae Ea/RT R= 8.314 J/mol K Integrated Rate...

  • rates of chemical reactions Plz help!! how do I find specific rate constant k, 1/T, In...

    rates of chemical reactions Plz help!! how do I find specific rate constant k, 1/T, In K thank you Rates of Chemical Reactions: Report Form Rate Law Summary: (a) From your measurements, what are the reaction orders with respect to each of the three reactants H;O; HOO (b) What is the rate expression (rate law) for the uncatalyzed reaction? Rate = K LT-] [H202) (c) What is the total reaction order? 2 3. Effect of Temperature on the Reaction Rate...

  • -4a 2a Arrhenius equation: k A exp(E/RT Rate Integated Rat Oder Equatisn Plat Sape Ideal gas:...

    -4a 2a Arrhenius equation: k A exp(E/RT Rate Integated Rat Oder Equatisn Plat Sape Ideal gas: pV-nRT; R = 8.314 /K-mol :0.08206 atm_L/mo Xa·m/(ruml: Molarity: M ansowe (mole)/Volume of solu in L; molality m- Foe (mole/mass of solvent (in kg) Part I.Short questions: (56 pt. No explanation is needed.) 1. (4pt) For the second-order reaction below, the initial concentration of reactant A is 0.24 M. f the rate constant for the reaction is 15 x 10 M'st, what is the...

  • Find the Laplace Transformation (10 points) u(t) (10 points) eu(t) (10 points) 30 cos wt u(t)...

    Find the Laplace Transformation (10 points) u(t) (10 points) eu(t) (10 points) 30 cos wt u(t) Use this ental infor- vorewo Pekes 1e of 500 K. Obtain a numerical value, includ- ing units, for each of the following partial derivatives for this gas. he values which the concentration of the andioen- antibody complex will be equal to the concen- tration of the unbound antibody. perimen- plies that consider- aG (b) (a) aT 19. The isomerization of glucose-6-phosphate G6P) to fructose-6-phosphate...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT