A 56-kg student runs at 6.4m/s, grabs a hanging 10.0-m-long rope, and swings out over a lake (Figure 1) . He releases the rope when his velocity is zero.
What is the angle ?
when he releases the rope?
Homework Answers
According to law of conservation of energy, equate PE and KE.
PE = KE
mgh = 1/2 m v^2
gh = v^2 / 2
h = v^2 / 2g
= 6.4^2 / ( 2 * 9.8 )
= 2.1 m
Determination of the angle:
Theta = cos^-1 [ (L-h) / L)
= cos^-1 [ ( 10 - 2.1 ) / 10 ]
= 37.8 degrees
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